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3 years ago

Match each atomic particle with the correct charge.

2 answers:

8 0

The proton is a postitive charge, therefore, being 1 (proton) matched to positive. Whilst neutron (2) is matched to neutral. Thus electron (3) is matched to negative.

saul85 [17]3 years ago

7 0

Protin 1
Neutron 0
Electron minus 1

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If the equilibrium constant for the reaction A 2B C 5/2 D has a value of 4.0, what is the value of the equilibrium constant for

nirvana33 [79]

Answer:

$K'=\frac{1}{16}$

Explanation:

Hello!

In this case, since the given reaction is:

$A+ 2B \rightleftharpoons C+ \frac{5}{2} D$

Whereas the equilibrium constant is:

$K=\frac{[C][D]^{5/2}}{[A][B]^2} =4.0$

However, the new target reaction reverses and doubles the initial reaction to obtain:

$2C+5D \rightleftharpoons 2A+4B$

Whereas the equilibrium constant is:

$K'=\frac{[A]^2[B]^4}{[C]^2[D]^5}$

Which suggest the following relationship between the equilibrium constants:

$K'=\frac{1}{K^2}$

So we plug in to obtain:

$K'=\frac{1}{4.0^2}\\\\K'=\frac{1}{16}$

Best regards!

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3 years ago

What would be the pH of a 0.180M solution of KOCN?

ratelena [41]

Answer:

8.37 ... see attached

Explanation:

I found it. Doc

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3 years ago

Which picture represents a liquid?

Lorico [155]

Answer:I think is "Particles are far apart and moving very quickly" good luck

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4 years ago

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The heat of fusion for water is 80. cal/g. how many calories of heat are released

Ray Of Light [21]

800 calories are released

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3 years ago

A flame test of a colorless solution gives a bright yellow color. When reacted with AgNO3 a white precipitate forms that dissolv

hichkok12 [17]

Answer:

The compound is Na2CO3

Explanation:

A flame test of a colorless solution gives a bright yellow color. The yellow color shows the presence of Sodium.

NaX + AgNO3 → AgX + NaNO3

When reacted with AgNO3 a white precipitate.

AgX + HNO3 → AgNO3 + H2O + CO2

A white precipitate will be formed when AgNO3 reacts with Sodium Chloride (NaCl) or Sodium carbonate(Na2CO3). (Also NaF, Na3PO4 are possible).

When HCL is added to the unknown solution, bubbles form.

Forming bubbles means that there is formed CO2 (and H20)

Na2X + 2HCl → 2NaCl + H2O + CO2

To form CO2 there is carbon needed

This shows that X is CO3 and the compound is Na2CO3

<u>To control:</u>

Na2CO3 + AgNO3 → Ag2CO3 + NaNO3

⇒Ag2Co3 is the white precipitate formed

This precipitate Ag2CO3 + HNO3 will disolve in AgNO3, CO2 and H2O

When Na2CO3 reacts with HCl there is formed NaCL together with bubbles ( which is CO2 and H2O).

The compound is Na2CO3

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4 years ago