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3 years ago

Match each atomic particle with the correct charge.

2 answers:

8 0

The proton is a postitive charge, therefore, being 1 (proton) matched to positive. Whilst neutron (2) is matched to neutral. Thus electron (3) is matched to negative.

saul85 [17]3 years ago

7 0

Protin 1
Neutron 0
Electron minus 1

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Which statement about polymers is true? A. Polymers are substances that have relatively large molecules. B. Oil and gas are the

igor_vitrenko [27]

Answer:

A.) Polymers are substances that have relatively large molecules

3 0

4 years ago

13. How many electrons are transferred in the following reaction? (The reaction is unbalanced.) Fe(s) + I'(aq) 12(s) + Fe3+(aq)

Nat2105 [25]

Answer : The correct option is, (C) 6

Explanation :

Oxidation-reduction reaction : It is a reaction in which oxidation and reduction reaction occur simultaneously.

Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.

Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.

The given unbalanced chemical reaction is,

$Fe(s)+I^-(aq)\rightarrow I_2(s)+Fe^{3+}(aq)$

Half reactions of oxidation and reduction are :

Oxidation : $Fe(s)\rightarrow Fe^{3+}+3e^-$ ......(1)

Reduction : $2I^-(aq)+2e^-\rightarrow I_2$ .......(2)

In order to balance the electrons, we multiply equation 1 by 2 and equation 2 by 3, we get:

Oxidation : $2Fe(s)\rightarrow 2Fe^{3+}+6e^-$ ......(1)

Reduction : $6I^-(aq)+6e^-\rightarrow 3I_2$ .......(2)

The overall balanced chemical reaction will be:

$2Fe(s)+6I^-(aq)\rightarrow 3I_2(s)+2Fe^{3+}(aq)$

From this reaction we conclude that the electrons are getting transferred from iron to iodine and the number of electrons transferred are 6 electrons.

Hence, the correct option is, (C) 6

5 0

3 years ago

What volume of water vapor would be produced from the combustion of 815.74 grams of propane (C3H8) with 1,006.29 grams of oxygen

d1i1m1o1n [39]

3940.2 is the volume of water vapour that would be produced from the combustion of 815.74 grams of propane ( $C_3H_8$ ) with 1,006.29 grams of oxygen gas, under a pressure of 1.05 atm and a temperature of 350. degrees C.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Stoichiometric calculations:

$C_3H_8(g) + 5 O_2(g)$ → $3 CO_2(g) + 4 H_2O(g)$

From the equation of the reaction, the mole ratio of propane to oxygen is 1:5.

Mole of 815.74 grams of propane = $\frac{ 815.74}{44.1 }$

Mole of 815.74 grams of propane = 18.49750567 moles

Mole of 1,006.29 grams of oxygen = $\frac{ 1,006.29}{32 }$

Mole of 1,006.29 grams of oxygen = 31.4465625 moles

Going by the mole ratio, it appears propane is limiting while oxygen is in excess.

From the equation, 1 mole of propane produces 4 moles of water vapour. Thus, the equivalent mole of water vapour will be:

18.49750567 moles x 4 = 73.99 moles.

Using the ideal gas equation:

PV = nRT

v = (73.99 x 0.08206 x 623) ÷ 0.96

v = 3940.2

Hence, 3940.2 is the volume of water vapour that would be produced from the combustion of 815.74 grams of propane ( $C_3H_8$ ) with 1,006.29 grams of oxygen gas, under a pressure of 1.05 atm and a temperature of 350. degrees C.

Learn more about the ideal gas here:

brainly.com/question/27691721

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2 years ago

समश्याजिक क्या है हाइड्रोजन का समस्थानिय<br>को समपस्य?

LUCKY_DIMON [66]

Answer:

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3 years ago

Is methane used as fule<br> gas true or false<br>

Hitman42 [59]

Answer:

its true methane is used as a fuel gas

Explanation:

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3 years ago