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agasfer [191]
2 years ago
14

Good morning! Can someone please answer this, ill give you brainliest and you will earn 50 points.

Physics
2 answers:
german2 years ago
5 0

Here are the answers

  • Temperature and energy:-Ocean and surface temperature
  • Atmospheric composition:- Carbon dioxide and other greenhouse gases
  • Ocean and water-Ocean acidification and sea level.
  • Cryosphere :-Sea ice and glaciers
Stels [109]2 years ago
4 0

Temperature and energy ➡️ <em>Surface</em><em> </em><em>temperature</em><em> </em><em>and</em><em> </em><em>ocean</em><em> </em><em>temperature</em><em> </em>

Atmospheric composition ➡️ <em>Carbon-dioxide</em><em> </em><em>and</em><em> </em><em>other</em><em> </em><em>greenhouse</em><em> </em><em>gases</em>

Ocean and water ➡️ <em>Ocean</em><em> </em><em>acidification</em><em> </em><em>and</em><em> </em><em>sea</em><em> </em><em>level</em>

Cryosphere<em> </em>➡️ <em>Sea</em><em> </em><em>ice</em><em> </em><em>and</em><em> </em><em>galciers</em>

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A 3.00 kg block moving 2.09 m/s
Talja [164]

Answer:11.64kgm/s

Explanation:

4 0
3 years ago
A disk of mass M and radius R rotates at angular velocity ω0. Another disk of mass M and radius r is dropped on top of the rotat
AleksandrR [38]

Answer:

\omega = \frac{(R^2\omega_o}{(R^2 + r^2)}

Explanation:

As we know that there is no external torque on the system of two disc

then the angular momentum of the system will remains conserved

So we will have

L_i = L_f

now we have

L_i = (\frac{1}{2}MR^2)\omega_o

also we have

L_f = (\frac{1}{2}MR^2 + \frac{1}{2}Mr^2)\omega

now from above equation we have

(\frac{1}{2}MR^2)\omega_o  = (\frac{1}{2}MR^2 + \frac{1}{2}Mr^2)\omega

now we have

\omega = \frac{MR^2\omega_o}{(MR^2 + Mr^2)}

\omega = \frac{(R^2\omega_o}{(R^2 + r^2)}

6 0
3 years ago
Three charges lie along the x axis. The positive charge q1 = 15 μC is at x= 2.0 m and the positive charge q2 = 6.0μC is at the o
Delicious77 [7]

Answer:

x = 0.775m

Explanation:

Conceptual analysis

In the attached figure we see the locations of the charges. We place the charge q₃ at a distance x from the origin. The forces F₂₃ and F₁₃ are attractive forces because the charges have an opposite sign, and these forces must be equal so that the net force on the charge q₃ is zero.

We apply Coulomb's law to calculate the electrical forces on q₃:

F_{23} = \frac{k*q_{2}*q_{3}}{x^2} (Electric force of q₂ over q₃)

F_{13} = \frac{k*q_{1}*q_{3}}{(2-x)^2} (Electric force of q₁ over q₃)

Known data

q₁ = 15 μC = 15*10⁻⁶ C

q₂ = 6 μC = 6*10⁻⁶ C

Problem development

F₂₃ = F₁₃

\frac{k*q_{2}*q_{3}}{x^2} = \frac{k*q_{1}*q_{3}}{(2-x)^2} (We cancel k and q₃)

\frac{q_2}{x^2}=\frac{q_1}{(2-x)^2}

q₂(2-x)² = q₁x²

6×10⁻⁶(2-x)² = 15×10⁻⁶(x)² (We cancel 10⁻⁶)

6(2-x)² = 15(x)²

6(4-4x+x²) = 15x²

24 - 24x + 6x² = 15x²

9x² + 24x - 24 = 0

The solution of the quadratic equation is:

x₁ = 0.775m

x₂ = -3.44m

x₁ meets the conditions for the forces to cancel in q₃

x₂ does not meet the conditions because the forces would remain in the same direction and would not cancel

The negative charge q₃ must be placed on x = 0.775 so that the net force is equal to zero.

6 0
3 years ago
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Shanti is riding on a train that is moving at a speed of 90 km/h. He is carrying a power cord for his phone that is 1.2 m long.
faltersainse [42]

Answer:equal to 1.2 m

Explanation: i took the test

3 0
3 years ago
Read 2 more answers
Science is the process of pursuing knowledge?
tatyana61 [14]

yes science is the process of pursuing knowledge this is because without science we would not know about our brains and our brains help us peruse knowledge

4 0
3 years ago
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