Select the correct answer.<br> Which word describes a goal that is poorly written?

A rectangular field is 300 meters long and 300 meters wide. What is the area of the field in square kilometers? Do not round you

dexar [7]

Answer:

Area of the rectangular field in kilometers is 0.09 $km^2$

Explanation:

We know that 1 kilometers = 1000 meters

since we need to find the area in unit of kilometers

therefore converting length and width into kilometers

1000 meters = 1 kilometers

300 meters = $\frac{300}{1000} = 0.3$

Likewise width = 0.3 km

Area = length x width

= 0.3km x 0.3 km

= 0.09 $km^2$

6 0

3 years ago

A 95 kg clock initially at rest on a horizontal floor requires a 650 n horizontal force to set it in motion. after the clock is

Tamiku [17]

The μs between the clock and floor is 650(M*g) and the μk between the clock and the floor is 560(M*g)

3 0

3 years ago

Read 2 more answers

What is the main tenet of mechanical philosophy

Lina20 [59]

Answer:362

Explanation:

i just want the points

4 0

2 years ago

Read 2 more answers

A ski lift has a one-way length of 1 km and a vertical rise of 200 m. The chairs are spaced 20 m apart, and each chair can seat

RSB [31]

Answer:

Explanation:

The question states that the chairs are spaced 20 m apart through a length of 1 km, or say, 1000 m.

It also does say that each chair weighs 250 kg, and as such the load is

M = 50 * 250

M = 12500.

Taking into consideration, the initial and final heights, we have

h1 = 0, h2 = 200 m

The work needed to raise the chairs,

W = mgh, where h = h2 - h1

W = 12500 * 9.81 * (200 - 0)

W = 2.54*10^7 J

The work is done at a rate of 10 km/h, and at a distance of 1 km, time taken would be

t = 1/10 = 0.1 h or say, 360 s

The power needed thus, is

P = W/t

P = 2.54*10^7 / 360

P = 68125 W, or 68 kW

Initial velocity, u = 0 m/s

Final velocity, v = 10 km/h = 2.78 m/s

Startup time, t is 17 s

Acceleration during the startup then is

a = (v - u)/t

a = 2.78/17

a = 0.163 m/s²

The power needed for the acceleration is

P = ½m [(v² - u²)/t]

P = ½ * 12500 * [2.78²/17]

P = 6250 * 0.455

P = 2844 W

3 0

2 years ago

A 6.2 kg ladder, 1.97 m long, rests on two sawhorses. Sawhorse A is 0.64 m from one end of the ladder, and sawhorse B is 0.17 m

Keith_Richards [23]

Answer:

42.69 N and 18.07 N

Explanation:

We are given that

Mass of ladder=6.2 kg

Length of ladder=1.97 m

Distance of Sawhorse A from one end=0.64 m

Distance of sawhorse B from other end=0.17 m

Let center of Ladder= $\frac{1.97}{2}=0.985 m$

Now, the distance of sawhorse A from center=r=0.985-0.64=0.345 m

Distance of sawhorse B from center of ladder=0.985-0.17=0.815 m

Force one ladder due to gravity=mg= $6.2\times 9.8=60.76N$

Where $g=9.8 m/s^2$

Torque applied on Sawhorse A= $0.345F_a$

Torque applied on Sawhorse B= $0.815F_b$

In equilibrium

$0.345F_a=0.815F_b$

$F_b=\frac{0.345}{0.815}F_a$

Total force= $F_a+F_b$

$F_a+\frac{0.345}{0.815}F_a=60.76$

$\frac{0.815F_a+0.345F_a}{0.815}=60.76$

$\frac{1.16}{0.815}F_a=60.76$

$F_a=\frac{60.76\times 0.815}{1.16}=42.69 N$

$F_b=\frac{0.345}{0.815}\times 42.69=18.07 N$

8 0

3 years ago

Select the correct answer. Which word describes a goal that is poorly written?