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user100 [1]
3 years ago
6

What is the approximate force the Earth would exert on a 15 kilogram object?plss i need asap!!!

Physics
1 answer:
DerKrebs [107]3 years ago
6 0

Answer:

The approximate mass of the object is. 1. 0.01 kg.

Explanation:

between the magnitude of the gravitational force exerted on Earth by the ... A 60-kg physics student would weigh 1560 N on the surface of planet X.

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A very long thin wire carries a uniformly distributed charge, which creates an electric field. The electric field is (2300 N/C ,
Leto [7]

Answer:

λ= 5.24 × 10 ⁻² nC/cm

Explanation:

Given:

distance r = 4.10 cm = 0.041 m

Electric field intensity E = 2300 N/C

K = 9 x 10 ⁹ Nm²/C

To find λ = linear charge density = ?

Sol:

we know that E= 2Kλ / r

⇒ λ = -E r/2K         (-ve sign show the direction toward the wire)

λ = (- 2300 N/C × 0.041 m) / 2 ×  9 x 10 ⁹ Nm²/C

λ = 5.24 × 10 ⁻⁹ C/m

λ = 5.24 nC/m = 5.24 nC/100 cm

λ= 5.24 × 10 ⁻² nC/cm

3 0
3 years ago
A wire 40cm long and of diameter 0.60mm has a resistance of 1.5 ohm what is the resistivity of the material of which it is made
zavuch27 [327]

Answer:

The resistivity of the wire is 1.05\times 10^{-6}\ \Omega-m

Explanation:

We have,

Length of a wire is 40 cm or 0.4 m

Diameter of a wire is 0.60 mm

Radius is 0.3 mm or 0.0003 m

Resistance of a wire is 1.5 ohm

Now we need to find the resistivity of the material of which it is made. The resistance of a wire in terms of its resistance, length and area is given by :

R=\rho \dfrac{l}{A}

\rho = resistivity

\rho=R \dfrac{\pi r^2}{l}\\\\\rho=1.5\times  \dfrac{3.14\times (0.0003 )^2}{0.4}\\\\\rho=1.05\times 10^{-6}\ \Omega-m

So, the resistivity of the wire is 1.05\times 10^{-6}\ \Omega-m.

3 0
3 years ago
A local FM radio station broadcasts at a frequency of 97.3 MHz. Calculate the energy of the frequency at which they are broadcas
levacccp [35]

Answer:

6.45×10¯²⁶ J

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 97.3 MHz

Energy (E) =?

Next, we shall convert 97.3 MHz to Hz. This can be obtained as follow:

1 MHz = 1×10⁶ Hz

Therefore,

97.3 MHz = 97.3 MHz × 1×10⁶ Hz / 1 MHz

97.3 MHz = 9.73×10⁷ Hz

Thus, 97.3 MHz is equivalent to 9.73×10⁷ Hz.

Finally, we shall determine the energy at which the frequency is broadcasting. This can be obtained as follow:

Frequency (f) = 9.73×10⁷ Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 9.73×10⁷

E = 6.45×10¯²⁶ J

Therefore, the energy at which the frequency is broadcasting is 6.45×10¯²⁶ J

5 0
3 years ago
A solid must be given​
alexdok [17]
I- what....? Lolllll
8 0
4 years ago
A system is a group of parts that can be considered one unit. Storm systems, ecosystems, and our bodies are natural systems. Car
iragen [17]
The best system to talk about would be a galaxy system. Energy does not enter the galaxy, but it does "recycle" its energy. For instance, when the life of a star comes to its end, it can go super nova. and all the energy from that star is then released back into the galaxy to form nebula's and then eventually into other stars. The energy inside of a galaxy can change frequently. It can be in the form of heat from a star, or it can change into gamma radiation from an explosion. Gases like helium and hydrogen come together and form a ball of gas creating the heat. Then the heat is dispersed leaving different types of radiation like gamma, ultra-violet, microwave, and infrared. Energy can leave a system by the local black holes. Black holes with shoot out Hawking radiation is when the black hole disperses its own energy out into space, also known as Black Hole Evaporation<span>. The energy from that black hole is then dispersed into the rest of the universe or possibly back into the galaxy from which it came from. </span>
3 0
3 years ago
Read 2 more answers
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