Given:
128g sample of titanium
2808J of heat energy
specific heat of titanium is 0.523 J/ g °C.
Required:
Change in temperature
Solution:
This can be solved
through the equation H = mCpT
where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.
Plugging in the
values into the equation
H = mCpT
2808J = (128g) (0.523
J /g °C) T
T
= 41.9 °C
<span>Physical properties are any properties of matter which can be perceived or observed without changing the chemical identity of the sample.</span>
Answer:
M = 0.177
Explanation:
First, we have to find the molar mass of potassium iodine (KI).
K = 39.098
I = 126.904
Now, add these values together to get the molar mass of KI
39.098 + 126.904 = 166.0028
Now, it's time to do a grams to moles conversion.
35.0 g KI * 
= 
= 0.212 mol KI
Now, we can find the molarity of this solution.
Molarity (M) = 
M = 
= 0.177 M
The molarity (M) of this solution is 0.177.
Answer:
I think it's D
Explanation:
I'm so sorry if that's wrong, hope it helps!
Answer:
Y³⁻ A non metal that gained three electrons.
V²⁺ A metal that lost two electron
Z²⁻ A non metal that gained two electrons
X³⁺ A metal that lost three electrons
Explanation:
Metals lost the electrons and form cation
while non metals gain the electrons and form anion.
Y³⁻
c) A non metal that gained three electrons.
Non metal gain three electrons and form anion with the charge of -3.
V²⁺
a) A metal that lost two electron
A metal lost two electrons and form cation with charge of +2.
Z²⁻
d) A non metal that gained two electrons
A non metal that gained two electrons and form anion with charge of -2.
X³⁺
b) A metal that lost three electrons
A metal that lost three electrons and form cation with charge of +3.
