Answer:
84.11 g/mol
Explanation:
A metal from group 2A will form the cation M²⁺, and the ion carbonate is CO₃²⁻, so the metal carbonate must be: MCO₃, and the reaction:
MCO₃(s) → MO(s) + CO₂(g)
For the stoichiometry of the reaction, 1 mol of MCO₃(s) will produce 1 mol of CO₂. Using the ideal gas law, it's possible to calculate the number of moles of CO₂:
PV = nRT , where P is the pressure, V is the volume(0.285 L), R is the gas constant (62.36 mmHg*L/mol*K), n is the number of moles, and T is the temperature (25 + 273 = 298 K).
69.8*0.285 = n*62.36*298
18583.28n = 19.893
n = 0.00107 mol
So, the number of moles of the metal carbonate is 0.00107. The molar mass is the mass divided by the number of moles:
0.0900/0.00107 = 84.11 g/mol
Answer:
<h2>
A. 2-phosphoglycerate
</h2>
Explanation:
Glycolysis is the process of breakdown of glucose into two 3-carbon molecules called pyruvate. The energy released during glycolysis is used to make ATP.
Enolase is the enzyme which plays very important role in glycolysis. In the 9th step of glycolysis, Enolase converts 2-phosphoglycerate into phosphoenolpyruvate.
This reaction of conversion of 2-phosphoglycerate to phosphoenolpyruvate is a reversible dehydration reaction.
Fluoride inhibits enolase, so when enolase is become non-functional then there is no convertion of 2-phosphoglycerate to phosphoenolpyruvate, so the concentraion of 2-phosphoglycerate is increases by the addition of fluoride.
Answer:
The answer is 44.0095.
Explanation:
1 grams CO2 is equal to 0.022722366761722 mole. so take that and multiply by 120 and you get 44.0095.
