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Naily [24]
2 years ago
9

Snape grows tired of these conceptual questions and thinks it's time for a problem. What is the retention factor if the distance

travelled by the solvent front is 2.00 cm, and the distance travelled by the ion is 0.40 cm?
Chemistry
1 answer:
MAVERICK [17]2 years ago
6 0

Answer:

The Retention factor (rf) value is = 0.2

Explanation:

  • Retention factor (Rf) is factor used substances that could be separated using Chromatography. Retention factor determines how fast the component can move on the chromatogram (stationary phase) after elution. Elution occurs when mobile phase (solvent) moves across the stationary phase when the solute has been spotted on the origin.
  • Retention factor (Rf) ranges from value between 0 and  1. The closer the value to 1, the faster it can move upon elution. Rf can be calculated.
  • Rf value = distance moved by the solute / distance moved by the solvent

             = 0.40cm / 2.00cm

             = 0.2

You might be interested in
Which location represents a period on a Periodic Table?   A. a vertical row   B. a horizontal row   C. a diagonal row on the per
prohojiy [21]
The periods inside the Periodic Table is B. a horizontal row, and is numbered 1 through 7


hope this helps
7 0
3 years ago
A 0.580 g sample of a compound containing only carbon and hydrogen contains 0.480 g of carbon and 0.100 g of hydrogen. At STP, 3
Sati [7]

Answer:

Molecular formula for the gas is: C₄H₁₀

Explanation:

Let's propose the Ideal Gases Law to determine the moles of gas, that contains 0.087 g

At STP → 1 atm and 273.15K

1 atm . 0.0336 L = n . 0.082 . 273.15 K

n = (1 atm . 0.0336 L) / (0.082 . 273.15 K)

n = 1.500 × 10⁻³ moles

Molar mass of gas = 0.087 g / 1.500 × 10⁻³ moles = 58 g/m

Now we propose rules of three:

If 0.580 g of gas has ____ 0.480 g of C _____ 0.100 g of C

58 g of gas (1mol) would have:

(58 g . 0.480) / 0.580 = 48 g of C  

(58 g . 0.100) / 0.580 = 10 g of H

 48 g of C / 12 g/mol = 4 mol

 10 g of H / 1g/mol = 10 moles

7 0
3 years ago
Calculate the pH of the solution that results when 20 mL of 0.2M HCOOH is mixed with 25mL of 0.2M NaOH solution.(post-equivalenc
Paul [167]

The pH of the solution : 12

<h3>Further explanation</h3>

Reaction

HCOOH    +     NaOH   ⇒     HCOONa   +   H₂O

mol HCOOH =

\tt 20~ml\times 0.2~M=4~mlmol

mol NaOH =

\tt 25~ml\times 0.2~M=5~mlmol

Mol NaOH>mol HCOOH ⇒ at the end of the reaction there will be a strong base remains from mol NaOH, so that the pH is determined from [OH⁻]

ICE method :

HCOOH    +     NaOH   ⇒     HCOONa   +   H₂O

4                          5

4                          4                     4                   4

0                          1                      1                    1

Concentration of [OH⁻] from NaOH :

\tt \dfrac{1~mlmol}{20+25~ml}=0.02

pOH=-log[OH⁻]

pOH=-log 10⁻²=2

pH+pOH=14

pH=14-2=12

3 0
3 years ago
Send Message
Ganezh [65]

Answer:

1 Atm

Explanation:

Dalton's law

The total pressure is 3 Atm so all you have to do is subtract the other partial pressures from 3

4 0
3 years ago
Read 2 more answers
The kilogram is the SI unit for mass
Leno4ka [110]

Answer:

yes

Explanation:

SI unit of mass is kilogram.

6 0
2 years ago
Read 2 more answers
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