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3 years ago

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show that the value of g is independent to the mass of the free falling body. The weigh of the person on the earth is 72 kg wt,

at what height it weight becomes 32kg wt?

1 answer:

alexdok [17]3 years ago

3 0

Answer:

I will show u

Explanation:

F=mg

F=GMm÷r(square)

Therefore mg=GMm÷r(square)

S all m on both sides will be cut.

Therefore mass of a free falling body is useless.

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Consider to cars traveling directly towards each other. Car A has twice the mass of Car B. In order for the cars to completely s

Greeley [361]

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3 years ago

The x component of vector is -27.3 m and the y component is +43.6 m. (a) What is the magnitude of ? (b) What is the angle betwee

lara [203]

Answer:51.44 units

Explanation:

Given

x component of vector is $-27.3\hat{i}$

y component of vector is $43.6\hat{j}$

so position vector is

$r=-27.3\hat{i}+43.6\hat{j}$

Magnitude of vector is

$|r|=\sqrt{27.3^2+43.6^2}$

$|r|=\sqrt{2646.25}$

|r|=51.44 units

Direction

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vector is in 2nd quadrant thus

$180-\theta =57.94$

$\theta =122.06^{\circ}$

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3 years ago

An acorn falls from a tree and hits the ground in 0.8 s. How far did the acorn fall . Use g = 9.8 m/s^2. Round your final result

mylen [45]

The distance covered by the acorn is 3.136 m.

<u>Explanation:</u>

The time taken for the acorn to hit the ground is 0.8 s. As it is a free fall, the acorn will be completely under the influence of gravity. So the acceleration will be acceleration due to gravity.

Then using the second law of equation,

$s=ut+\frac{1}{2}gt^{2}$

Since the initial velocity and time is zero, then the time taken to reach the ground is stated as 0.8 s, so

$s=0+\left(\frac{1}{2} \times 9.8 \times 0.8 \times 0.8\right)=\frac{6.272}{2}=3.136 \mathrm{m}$

So the distance covered by the acorn is 3.136 m.

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asambeis [7]

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NARA [144]

Answer:

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Explanation:

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3 years ago

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