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kherson [118]
3 years ago
14

Can anyone plz send me the solved questions this is Energy chapter ​

Physics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

34' jhm

Explanation:

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"A student bikes to school by traveling first dN = 0.900" and "Similarly, let d⃗ W be the displacement vector corresponding to t
raketka [301]

Complete Question

A student bikes to school by traveling first dN = 0.900 miles north, then dW = 0.300 miles west, and finally dS = 0.100 miles south.

Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form.

Express your answer as two numbers separated by a comma. Be careful with your signs.

Answer:

The value is  dT  =  ( -0.3,  0.8)

Explanation:

From the question we are told that

   The first displacement is  dN  =  0.900 \  due  \  North i.e positive  y-axis

   The  second displacement is  dW =  0.300 \  miles  \  due \  west i.e negative  x-axis

   The final displacement is  dS =  0.100 \  miles \ due \ south i.e  negative  y-axis

Generally dW in component for is  

      dW =  (-0.3 ,  0)  

Generally the  total displacement of the student is mathematically represented as

     dT  =  ( -0.3,  (0.90 - 0.10))

      dT  =  ( -0.3,  0.8)

 

   

   

6 0
3 years ago
Two wires are parallel and one is directly above the other. Each has a length of 50.0 m and a mass per unit length of 0.020 kg/m
ivann1987 [24]

Answer: The time required for the impluse passing through each other is approximately 0.18seconds

Explanation:

Given:

Length,L = 50m

M/L = 0.020kg/m

FA = 5.7×10^2N

FB = 2.5×10^2N

The sum of distance travelled by each pulse must be 50m since each pulse started from opposite ends.

Ca(t) + CB(t) = 50

Where CA and CB are the velocities of the wire A and B

t = 50/ (CA + CB)

But C = Sqrt(FL/M)

Substituting gives:

t = 50/ (Sqrt( FAL/M) + Sqrt(FBL/M))

t = 50/(Sqrt 5.7×10^2/0.02) + (Sqrt(2.5×10^2/0.02))

t = 50 / (168.62 + 111.83)

t = 50/280.15

t = 0.18 seconds

4 0
3 years ago
Read 2 more answers
A car moves in a straight line at a speed of 68.5 km/h. How far (in km) will the car move in 5.45 minutes at this speed?
AlekseyPX
If you divide 68.5 km/h by 60 (the minutes in an hour) and then you get 1.141 then you multiply it by 5.45 and you get 6.222!


Your Answer is 6.222!!!!
5 0
3 years ago
This is a small rocky body that orbits the sun, and when close to the sun exhibit a small tail of ice and gas.
Over [174]
This is a comet. It is also called a dirty snowballs.
3 0
3 years ago
A racing car on a straight accelerates from 100mph to 316 mph in three seconds what is the acceleration?
omeli [17]

Answer:

72mph/sec

Explanation:

The car goes from 100mph to 316mph in three seconds. Meaning it increases its speed by (316 - 100)mph in three seconds. That is 216 mph increase in three seconds. So, we divide the speed increase by the amount of time the increase occurred over. We get:

216mph / 3sec = 72mph/sec, our final answer

Hope it made sense. I would appreciate Brainliest, but no worries.

8 0
3 years ago
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