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vodomira [7]
3 years ago
6

Consider a cell membrane at 298K which has glucose at the concentration of 200mM inside the cell and 20 mM outside the cell, wit

h the voltage being 50 mV lower in the interior. Calculate the molar free energy difference for transporting a glucose molecule from the exterior to the interior of the cell.A. -2.7 kJ/molB. -5.7 kJ/molC. +2.7 kJ/molD. +5.7 kJ/mol
Chemistry
1 answer:
OleMash [197]3 years ago
4 0

Answer:

D. +5.7 kJ/mol

Explanation:

Molar free energy (ΔG) in the transportation of uncharged molecules as glucse through a cell membrane from the exterior to the interior of the cell is defined as:

ΔG = RT ln C in / C out

knowing R is 8,314472 kJ/molK; T is 298K Cin = 200mM and Cout = 20mM

ΔG = 5,7 kJ/mol

Right answer is:

D. +5.7 kJ/mol

I hope it helps!

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8_murik_8 [283]

To compute the required mass of the element to form the given molecules, we'll use the general formula shown below:

{eq}\displaystyle m_1=\frac{M_1}{M_2}\times m_2 {/eq}, where,

{eq}M_1 {/eq} is the molecular weight of the element.

{eq}M_2 {/eq} is the molecular weight of the given molecule.

{eq}m_2 {/eq} is the mass of the given molecule.

Answer and Explanation:

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The given value is:

The value of the mass of the water molecule is {eq}m_2=\rm 50\ grams {/eq}.

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Learn more about this topic:

Formula for Mass: Definition & Examples

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Chapter 28 / Lesson 42

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What is mass? Learn the mass definition and how to find the mass of an object using the mass formula. See common mass characteristics and properties.

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2 years ago
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Answer:

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Is there a difference between a homogeneous mixture of hydrogen and oxygen in a 2:1 ratio and a sample of water vapor?
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Answer:

Yes

Explanation:

There is a difference between the homogeneous mixture of the hydrogen and the oxygen in a 2:1 ratio and the sample of the water vapor.

In the homogeneous mixture of the hydrogen and the oxygen which are present in the ratio, 2:1 , the elements are not chemically combined. They are explosive also as both shows their specific properties. They can be separated by physical means (Condensation, diffusion).

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What kind of solution would you have if it contained 50 grams of sodium chloride in 100 mL of water at 30˚C?
Svetlanka [38]

Answer:

Supersaturated solution.

Explanation:

Hello!

In this case, according to the types of solution in terms of the relative amounts of solute and solvent, we can define a point called solubility at which the amount of solute is no longer dissolved in the solvent; thus, a value of solute/solvent less than the solubility is related to unsaturated solutions, equal to the solubility is related to the saturated solutions and more than the solubility to supersaturated solutions.

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