Hello! I'm not too knowledgeable on this topic, but I do know that ammonification is caused through different inorganic reactions. Or to metabolism systems of organisms. I also found it is a process in which nitrate reduction to nitrite is followed by the six-electron reduction of nitrite to ammonium.
-- Mr. Galonski looks at himself in the mirror while he shaves in the morning, using visible light.
-- On his way to work, he listens to music and news, taking advantage of all the radio waves around.
-- While walking from his car to his office, he takes his jacket off and rolls up his sleeves, so his arms can soak up some ultraviolet from the sun, and get a little bit of color.
-- Mister Galonski is actually DOCTOR Galonski DDS ... a dentist. He uses a machine that produces X-rays, to take pictures of his patients' teeth and jaws. He glues the pictures into a big scrap-book that he keeps on the coffee table in his living room.
Answer:
4 m/s² down
Explanation:
We'll begin by calculating the net force acting on the object.
The net force acting on the object from the left and right side is zero because the same force is applied on both sides.
Next, we shall determine the net force acting on the object from the up and down side. This can be obtained as follow:
Force up (Fᵤ) = 15 N
Force down (Fₔ) = 25 N
Net force (Fₙ) =?
Fₙ = Fₔ – Fᵤ
Fₙ = 25 – 15
Fₙ = 10 N down
Finally, we shall determine the acceleration of the object. This can be obtained as follow:
Mass (ml= 2.5 Kg
Net force (Fₙ) = 10 N down
Acceleration (a) =?
Fₙ = ma
10 = 2.5 × a
Divide both side by 2.5
a = 10 / 2.5
a = 4 m/s² down
Therefore, the acceleration of the object is 4 m/s² down
Answer:
Q = 29.4 x 10⁻⁹ C.
Explanation:
Electric field due to a charge Q at distance d is given by coulomb law as follows
Electric field
E = k Q /d²
where for air k which is a constant is 9 x 10⁹
Given E = 32.08 , d = 2.84 m
Putting these values in the relation above, we have
![[tex]32.08=\frac{9\times 10^9\times Q}{(2.84)^2}](https://tex.z-dn.net/?f=%5Btex%5D32.08%3D%5Cfrac%7B9%5Ctimes%2010%5E9%5Ctimes%20Q%7D%7B%282.84%29%5E2%7D)
[/tex]
Q = 29.4 x 10⁻⁹ C.
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