To operate a mixer circuit , Anne should use a (motor, buzzer, bulb, or battery) to transfer electric energy into motion. She should also use a (switch, resistor, buzzer, or bulb) to start and stop the flow of current.
An electric-powered circuit consists of a device that gives energy to the charged particles constituting the modern-day, consisting of a battery or a generator; devices that use cutting-edge, including lamps, electric cars, or computer systems; and the connecting wires or transmission traces.
An electrical circuit is an interconnection of electrical components or a version of such an interconnection, consisting of electrical elements. an electrical circuit is a network along with a closed loop, giving a go-back direction for the cutting-edge.
An electrical circuit consists of a source of electrical strength, two wires that can convey electric power present day, and a mild bulb. One stop of both the wires is hooked up to the terminal of a mobile at the same time as their free ends are related to the light bulb. the electric circuit is damaged while the bulb is switched off.
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Answer:
Explanation:
Sam mass=75kg
Height is 50m
20° frictionless slope
Horizontal force on Sam is 200N
According to the work energy theorem, the net work done on Sam will be equal to his change in kinetic energy.
Therefore
Wg - Ww =∆K.E
Note initial the body was at rest at top of the slope.
Then, ∆K.E is K.E(final) - K.E(initial)
K.E Is given as ½mv²
Since initial velocity is zero then, K.E(initial ) is zero
Therefore, ∆K.E=½mVf²
Wg is work done by gravity and it is given by using P.E formulas
Wg=mgh
Wg=75×9.8×50
Wg=36750J
Ww is work done by wind and it's is given by using formulae for work
Work=force × distance
Ww=horizontal force × horizontal distance
Using Trig.
TanX=opposite/adjacent
Tan20=h/x
x=h/tan20
x=50/tan20
x=137.37m
Then,
Ww=F×x
Ww=200×137.37
We=27474J
Now applying the formula
Wg - Ww =∆K.E
36750 - 27474 =½×75×Vf²
9276=37.5Vf²
Vf²=9275/37.5
Vf²= 247.36
Vf=√247.36
Vf=15.73m/s
A conductor allows electricity to flow through it.
3 protons should be your answer
Ke=34J. The canoe's kinetic energy floating downriver at a speed of 2m/s and 17kg mass is 34J.
This is a problem of kinetic energy, which is a form of energy, known as motion energy. The kinetic energy of an object is that which is produced because of its movements that depends on its mass and velocity.
The kinetic energy is represented by the following formula: Ke = ½ mv². The kinetic energy is measured in Joules (J), the mass in kilograms (kg) and the speed in meters over seconds (m/s).
A small 17kg canoe is floating downriver at a speed of 2m/s. Let's calculate canoe's kinetic energy.
Ke= (17kg)[(2m/s)²]/2= 68/2 kg m²/s²=34J
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