B.) At higher temperature and low pressure.
Hope this helps you.
Answer is: 180 <span>grams of 2.5% "h" cream should be mixed.
</span>ω₁ = 2.5% ÷ 100% = 0.025.
ω₂ = 0.25% ÷ 100% = 0.0025.
ω₃ = 1% ÷ 100% = 0.01.
m₂ = 360 g.
m₃ = m₁ + 360 g.
m₁ = ?.
ω₁ · m₁ + ω₂ · m₂ = ω₃ · m₃.
0.025 · m₁ + 0.0025 · 360 g = 0.01 · (m₁ + 360 g).
0.025 · m₁ + 0.9 g = 0.01 · m₁ + 3.6 g.
0.015 · m₁ = 2.7 g.
m₁ = 180 g.
Answer:
The net charge on each lysine molecule would be -1.
Explanation:
- <u>When the pH is above 2.2</u> the deprotonated form of the carboxylic acid is more present, while the amino group and side chain (which is also amino) remain protonated (with a positive charge):
R-COOH ↔ R-COO⁻
R-NH₃⁺
R'-NH₃⁺
Net charge = +1
- <u>When pH is above 9.0</u>, the carboxyl group remains deprotonated, while the amino group is deprotonated and the side chain is protonated:
R-COOH ↔ R-COO⁻
R-NH₂
R'-NH₃⁺
Net charge = 0
- <u>When pH is above 10.5</u>, the carboxyl group remains deprotonated, while both the amino group and the side chain are deprotonated:
R-COOH ↔ R-COO⁻
R-NH₂
R'-NH₂
Net charge = -1
So at pH=13 (which is above 10.5) the net charge is -1.
