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2 years ago

If gas is initially at 350L and 500k then changes to 295K what is the new volume

Chemistry

1 answer:

Dimas [21]2 years ago

5 0

<h2>Hello!</h2>

The answer is:

The new volume is equal to 206.5 L.

To solve this problem, we need to assume that the pressure is constant, and use the Charle's Law equation, so, solving we have:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

We are given:

$V_1=350L\\T_1=500K\\T_2=295K$

Then, using the Charle's Law equation, we have:

$\frac{350L}{500K}=\frac{V_2}{295K}$

$\frac{350L}{500K}=\frac{V_2}{295K}\\\\V_2=\frac{350L}{500K}*295K=206.5L$

Hence, we have that the new volume is equal to 206.5 L.

Have a nice day!

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What is the major role of the nuclear regulatory commission

garik1379 [7]

Monitoring and regulating nuclear waste generated and issues associated to it the US.

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2 years ago

The average propane cylinder for a residential grill holds approximately 18 kg of propane. how much energy (in kj) is released b

Angelina_Jolie [31]

Let's begin with the basic values that will be used in the solution.

The formula of propane is C3H8. It is an alkane, a hydrocarbon with the general formula of CnH2n+2. Notice that hydrocarbons have only Carbon and Hydrogen atoms. Its molar mass (M) is 44 g.

Molar Mass Calculation is done as like that
C=12 g/mol, H=1 g/mol. 1 mole propane has 3 moles Carbon atoms and 8 mole Hydrogen atoms. M(C3H8)= 3*12+ 8*1= 44 g

Combustion reaction of hydrocarbons gives carbon dioxide and water by releasing energy. That energy is called as enthalpy of combustion (ΔHc°).

ΔHc° of propane equals -2202.0 kj/mol. Burning of 1 mole C3H8 releases 2202 kj energy. Minus sign only indicates that the energy is given out ( an exothermic reaction ).

Let's write the combustion reaction.
C3H8 + O2 ---> CO2 + H20 (unbalanced) ΔHc° = -2202 kj/mol

Now, we calculate mole of 20 kg propane. Convert kilogram into gram since we use molar mass is defined in grams.
mole=mass/molar mass ; n=m/M ; n= 20000 g /44 (g/mol)=454 mole

1 mole propane releases 2202 kj energy.
454 mole propane release 2202 kj *454= 1000909 kj

The answer is 1000909 kj.

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3 years ago

In another experiment, if 80 xo3 molecules react with 104 brz3 molecules how many br2 molecules will be produced which reactant

BaLLatris [955]

This is an incomplete question, here is a complete question.

The balanced chemical reaction is:

$6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2$

In another experiment, if 80 $XO_3$ molecules react with 104 $BrZ_3$ molecules. How many $Br_2$ molecules will be produced which reactant will be used up in the reaction.

Answer : The number of molecules of $Br_2$ will be, 52 molecules and $BrZ_3$ reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

Explanation :

The balanced chemical reaction is:

$6XO_3+8BrZ_3\rightarrow 6XZ_4+4Br_2+9O_2$

First we have to determine the limiting reagent.

From the balanced reaction we conclude that,

As, 8 molecules of $BrZ_3$ react with 6 molecule of $XO_3$

So, 104 molecules of $BrZ_3$ react with $\frac{104}{8}\times 6=78$ molecule of $XO_3$

From this we conclude that, $XO_3$ is an excess reagent because the given moles are greater than the required moles and $BrZ_3$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the molecules of $Br_2$

From the reaction, we conclude that

As, 8 molecules of $BrZ_3$ react to give 4 molecules of $Br_2$

So, 104 molecules of $BrZ_3$ react to give $\frac{104}{8}\times 4=52$ molecules of $Br_2$

Hence, the number of molecules of $Br_2$ will be, 52 molecules and $BrZ_3$ reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.

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2 years ago

How many moles are present in 2.7 liters of Argon gas at STP?

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2 years ago

reativity of alkali metals increases down the group while reativity decreases down the group in helogens

BigorU [14]

Complete question is;

Chemical reactivity of alkali metals increases down the group while reactivity of halogens decreases down the group. Give reasons

Answer:

Explained below

Explanation:

Alkali metals exhibit reactivity due to their electropositivity. Now, for alkalis, their electro-positivity increases down their group. Since their reactivity increases with increase in electropositivity, it means their reactivity also increases down the group.

Whereas, the reactivity of halogens occurs as a result of their electronegativity. Now, electronegativity for halogens decreases down the group. Since their reactivity decreases with decrease in electronegativity, it means that their reactivity will also decrease down the group.

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