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VARVARA [1.3K]
3 years ago
9

I was named after the man that developed the periodic table.

Chemistry
2 answers:
valina [46]3 years ago
4 0
Einsteinium
I hope that helps
d1i1m1o1n [39]3 years ago
4 0

Answer: Mendelevium

Explanation:

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MakcuM [25]

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Earth's gravity is strong enough to hold onto its atmosphere and keep it from drifting into space.

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3 years ago
Ag + HCl --&gt; ?<br> a) No reaction<br> b) AgCl + H2<br> c) AgCl + H2O<br> PLEASE HELP
Volgvan

Answer:

AgCl + H2 - Chemical Equation Balancer.

8 0
3 years ago
Read 2 more answers
Oxidation state of Nitrogen in N2O5​
balandron [24]

Explanation:

Oxidation state of Nitrogen in N2O5 is +5

7 0
2 years ago
Lead(II) nitrate is added slowly to a solution that is 0.0800 M in Cl− ions. Calculate the concentration of Pb2+ ions (in mol /
barxatty [35]

Answer:

[Pb^{2+}]=3.9 \times 10^{-2}M

this is the concentration required to initiate precipitation

Explanation:

PbCl_2  ⇄ Pb^{2+}+2Cl^-

Precipitation starts when ionic product is greater than solubility product.

Ip>Ksp

Precipitation starts only when solution is supersaturated because solution become supersaturated then it does not stay in this form and precipitation starts itself only solution become saturated.

This usually happens when two solutions containing separate sources of cation and anion are mixed together and here also we are mixing lead (||)nitrate solution(source of lead(||)) into the Cl- solution.

Ip=[Pb^{2}][2Cl^-]^2=Ksp

Ksp=2.4\times 10^{-4}

lets solubility=S

[Pb^{2+}] = S

[Cl^-]=2S

Ksp=[Pb^{2+}]\times [Cl^-]^2

Ksp=S \times (2S)^2

Ksp=4S^3

S=\sqrt[3]{\frac{Ksp}{4} }

S=3.9\times 10^{-2}

[Pb^{2+}]=3.9 \times 10^{-2}M this is the concentration required to initiate precipitation

4 0
3 years ago
How many ions are in 1.50 grams of Na+?
Jobisdone [24]

Answer:

= 0.0652 moles

Explanation:

I hope it helps you

7 0
3 years ago
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