Answer:
Complete Python code along with step by step explanation and output results is provided below.
Python Code with Explanation:
# create a function named getNumber(c)
# Using if elif conditions implement the phonetic character to number conversion for both lower case and upper case letters.
def getNumber(c):
if(c=='a' or c== 'b' or c=='c' or c=='A' or c == 'B' or c == 'C'):
return (2)
elif(c=='d' or c== 'e' or c=='f' or c=='D' or c == 'E' or c == 'F'):
return (3)
elif(c=='g' or c== 'h' or c=='i' or c=='G' or c == 'H' or c == 'I'):
return (4)
elif(c=='j' or c== 'k' or c=='l' or c=='J' or c == 'K' or c == 'L'):
return (5)
elif(c=='m' or c== 'n' or c=='o' or c=='M' or c == 'N' or c == 'O'):
return (6)
elif(c=='p' or c== 'q' or c=='r' or c=='s' or c=='P' or c == 'Q' or c == 'R' or c == 'S'):
return (7)
elif(c=='t' or c== 'u' or c=='v' or c=='T' or c == 'U' or c == 'V'):
return (8)
elif(c=='w' or c== 'x' or c=='y' or c=='z' or c=='W' or c == 'X' or c == 'Y' or c == 'Z'):
return (9)
else:
return (0)
# Get input string from the user
string = input("Please enter any string to convert! ")
# find the length of the input string for the for loop
length = len(string)
# Run a for loop length number of times to call the function getNumber(c) and convert the characters into numbers
for i in range(length):
c = string[i]
k = getNumber(c)
if(k==0):
print (c,end="")
else:
print (k,end="")
# end="" is used so that all numbers displayed in one line
Output:
Please enter any string to convert! Hello WORLD
43556 96753
Please enter any string to convert! Brainly
2724659
