The specific heat of mercury is 149.4 J/(kgK)
Explanation:
When a substance is supplied with an amount of energy Q, its temperature increases according to the equation:

where
is the increase in temperature
m is the mass of the sample
is its specific heat capacity
For the sample of mercury in this problem we have
Q = 275 J
m = 0.450 kg

Therefore, by re-arranging the equation we find the mercury's specific heat:

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Answer:

Explanation:
Given that,
The current in the loop, I = 2 A
The radius of the loop, r = 0.4 m
We need to find the magnetic field at a distance 0.09 m along the axis and above the center of the loop. The formula for the magnetic field at some distance is given as follows :

Put all the values,

So, the required magnetic field is equal to
.
Answer:
a) Yes
b) No
Explanation:
In the first case, part a, yes we can say for certainty that cylinderical symmetry holds. Why so? You may ask. This is because from the question, we are told that the length of the rod is 300 cm. And this said length is longer than the distance to the point from the center of the rod, which is 5 cm.
In the second half of the question, I beg to disagree that cylindrical symmetry holds. Again, you may ask why, this is because the length of the rod in this case, is having the same order of magnitude as the distance to the center of the rod. Thus, it is not symmetrical.
Answer:
Red light
Explanation:
This because All interference or diffraction patterns depend upon the wavelength of the light (or whatever wave) involved. Red light has the longest wavelength (about 700 nm)
The correct answer is
<span>c) very small and very large
Let's see this with a few examples:
1) if we have a very small number, such as
</span>

<span>we see that we can write it easily by using the scientific notation:
</span>

<span>2) Similarly, if we have a very large number:
</span>

<span>we see that we can write it easily by using again the scientific notation:
</span>

<span>
</span>