Answer: attractive
Explanation:
According to Newton's law of Gravitation, the gravitational force exerted between two bodies of masses
and
and separated by a distance
is equal to the product of their masses and inversely proportional to the square of the distance:
Where:
is the Gravitational Constant
and
are the masses of the objects
is the distance between the objects
It should be noted: this force is a central force and is attractive.
(a) 10N
<h2>Explanation:</h2>The sketch of the two cases has been attached to this response.
<em>Case 1: The box is pushed by a horizontal force F making it to move with constant velocity.</em>
In this case, a frictional force is opposing the movement of the box. As shown in the diagram, it can be deduced from Newton's law of motion that;
∑F = ma -------------------(i)
Where;
∑F = effective force acting on the object (box)
m = mass of the object
a = acceleration of the object
∑F = F -
m = 50kg
a = 0 [At constant velocity, acceleration is zero]
<em>Substitute these values into equation (i) as follows;</em>
F - = m x a
F - = 50 x 0
F - = 0
F = -------------------(ii)
<em>Case 2: The box is pushed by a horizontal force 1.5F making it to move with a constant velocity of 0.1m/s²</em>
In this case, the same frictional force is opposing the movement of the box.
∑F = 1.5F -
m = 50kg
a = 0.1m/s²
<em>Substitute these values into equation (i) as follows;</em>
1.5F - = m x a
1.5F - = 50 x 0.1
1.5F - = 5 ---------------------(iii)
<em>Substitute </em><em> = F from equation (ii) into equation (iii) as follows;</em>
1.5F - F = 5
0.5F = 5
F = 5 / 0.5
F = 10N
Therefore, the value of F is 10N
<em />
Answer:
The speed of the big fish after swallowing the small fish is 0.38 m/s.
Explanation:
Consider west to east direction as positive and the opposite direction as negative.
Given:
Mass of big fish (m₁) = 12.0 kg
Initial velocity of big fish (u₁) = 75 cm/s = 0.75 m/s
Mass of small fish (m₂) = 1 kg
Initial velocity of small fish (u₂) = -4 m/s (Direction is opposite to u₁)
After swallowing the small fish, both the fishes move together with same velocity. Let the velocity be 'v'.
So, as there are no effects of drag or any other forces, the given scenario can be considered as a case of inelastic collision where the objects move together with same velocity after collision.
The momentum is conserved in inelastic collision. Therefore,
Initial momentum of the fishes = Final momentum of the fishes
Now, plug in the given values and solve for 'v'. This gives,
Therefore, the speed of the big fish after swallowing the small fish is 0.38 m/s