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sergejj [24]
2 years ago
6

. Determine if approximate cylindrical symmetry holds for the following situations. State why or why not. (a) A 300-cm long copp

er rod of radius 1 cm is charged with 500 nC of charge and we seek electric field at a point 5 cm from the center of the rod. (b) A 10-cm long copper rod of radius 1 cm is charged with 500 nC of charge and we seek electric field at a point 5 cm from the center of the rod.
Physics
1 answer:
MA_775_DIABLO [31]2 years ago
6 0

Answer:

a) Yes

b) No

Explanation:

In the first case, part a, yes we can say for certainty that cylinderical symmetry holds. Why so? You may ask. This is because from the question, we are told that the length of the rod is 300 cm. And this said length is longer than the distance to the point from the center of the rod, which is 5 cm.

In the second half of the question, I beg to disagree that cylindrical symmetry holds. Again, you may ask why, this is because the length of the rod in this case, is having the same order of magnitude as the distance to the center of the rod. Thus, it is not symmetrical.

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The question is incomplete, the options are;

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Answer:

P=RI^2

P=V^2/R

P=VI

Explanation:

Power is the rate at which energy is changing in a circuit. It is shown by the formulas outlined above from the group of answer choices. Since the current (I), voltage (V), and resistance (R) were mentioned in the question, any of three three formulas could be used to obtain the power drawn by the conductor.

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2 years ago
An electric motor rotating a workshop grinding wheel at 1.00 × 10² rev/min is switched off. Assume the wheel has a constant nega
ololo11 [35]

An electric engine turning a workshop sanding rotation at 1.00 × 10² rev/min is switched off. Take the wheel includes a regular negative angular acceleration of volume 2.00 rad/s². 5.25 moments long it takes the grinding rotation to control.

<h3>What is negative angular acceleration?</h3>
  • A particle that has a negative angular velocity rotates counterclockwise.
  • Negative angular acceleration () is a "push" that is hence counterclockwise.
  • The body will speed up or slow down depending on whether and have the same sign (and eventually go in reverse).
  • For instance, when an object rotating counterclockwise slows down, acceleration would be negative.
  • If a rotating body's angular speed is seen to grow in a clockwise direction and decrease in a counterclockwise direction, it is given a negative sign.
  • It is known that a change in the linear acceleration correlates to a change in the linear velocity.

Let t be the time taken to stop.

ω = 0 rad/s

Use the first equation of motion for rotational motion

ω = ωo + α t

0 = 10.5 - 2 x t

t = 5.25 second

To learn more about angular acceleration, refer to:

brainly.com/question/21278452

#SPJ4

7 0
1 year ago
How should the student change the circuit to give negative values for current and
dmitriy555 [2]

Answer:

Flip the cell.

Explanation:

This reverses direction of energy transfer.

Alternatively, flip ammeters and voltmeters to give negative readings.

what do penguins eat for lunch?

Ice-burgers!

3 0
2 years ago
The fishing pole shown here is an example of a lever. Which statement describes the fishing pole's mechanical advantage?
luda_lava [24]

Answer:

Explanation:

The person will exert a much larger force to take a fish out of the water than the fish itself weighs. The advantage of the fishing pole, however, is that it moves the fish a large distance, from the water to the boat or the shore.

8 0
2 years ago
After the box comes to rest at position x₁, a person starts pushing the box, giving it a speed v₁. When the box reaches position
Vesna [10]

Answer:

W_p = \frac{1}{2}mv_1^2

Explanation:

As we know that box is initially at rest

So we will have

v_i = 0

now as it will be displaced from initial position to final position then final speed of the box is reached to

v_f = v_1

now we know by work energy theorem that work done by all the forces on the box will be equal to the change in kinetic energy

So here we will have

W_p = \frac{1}{2}m(v_f^2 - v_i^2)

W_p = \frac{1}{2}m(v_1^2 - 0)

W_p = \frac{1}{2}mv_1^2

8 0
3 years ago
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