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lianna [129]
3 years ago
9

In the presence of excess oxygen, methane gas burns in a constant-pressure system to yield carbon dioxide and water:

Chemistry
1 answer:
Marina CMI [18]3 years ago
6 0

Explanation:

in the presence of excess oxygen methane burns to prduce carbon (iv) oxide and water ....this is called complete combustion...

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During a lunar eclipse, the moon appears to be darkened because _______________ is casting a shadow on it.
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Which of the following is not equal to 485 L?
ELEN [110]

Answer:

4.85 * 10^4\ mL

Explanation:

Given

485 L

Required

Determine the measurement not equal to 485L

0.485\ kL

<em>From standard unit of conversion;</em>

1 KL = 1000 L

<em>Multiply both sides by 485</em>

485 * 1 KL = 485 * 1000 L

485KL = 485000L

<em>Divide both sides by 1000</em>

\frac{485KL}{1000} = \frac{485000L}{1000}

0.485KL = 485L  ---- This is equivalent

---------------------------------------------------------------------------------------------

4.85 * 10^4\ mL

<em>From standard unit of conversion;</em>

1000 mL = 1 L

<em>Multiply both sides by 485</em>

485 * 1000 mL = 1 L * 485

485000\ mL = 485\ L

Convert to standard form

4.85 * 10^5\ mL = 485\ L

Hence; 4.85 * 10^4\ mL is not equivalent to 485L

---------------------------------------------------------------------------------------------

48500 \ cL

<em>From standard unit of conversion;</em>

100 cL = 1 L

<em>Multiply both sides by 485</em>

485 * 100 cL = 1 L * 485

48500\ cL = 485\ L

Convert to standard form

4.85 * 10^4\ cL = 485\ L ---- This is equivalent

---------------------------------------------------------------------------------------------

4.85 * 10^8 \ μL

<em>From standard unit of conversion;</em>

1000000 μL = 1 L

<em>Multiply both sides by 485</em>

485 * 1000000uL  = 1 L * 485

485000000uL = 485\ L

Convert to standard form

4.85 * 10^8\ uL = 485\ L ---- This is equivalent

From the list of given options;

4.85 * 10^4\ mL is not equivalent to 485L

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3 years ago
Within each energy level there are different sublevels that are created. Those electrons that have the lowest
Volgvan
It’s option D cause we know that S orbital is spherical
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