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2 years ago

HELP I HAVE 14 MINUTES!!

Chemistry

2 answers:

Whitepunk [10]2 years ago

7 0

3- b, d, and g. a neutron has no charge and has mass.

ki77a [65]2 years ago

4 0

Answer:

2 one

Explanation:

is right coz I think

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Elements that are generally shiny when smooth and clean.

Verdich [7]

Metals are elements that are generally shiny when smooth and clean

5 0

3 years ago

Why can't air exist in space, but gas can????

MakcuM [25]

Answer:

Earth's gravity is strong enough to hold onto its atmosphere and keep it from drifting into space.

8 0

2 years ago

2. A sample of neon gas has a volume of 87.6 L at STP. How many moles are present?

PSYCHO15rus [73]

Answer:

3.91 moles of Neon

Explanation:

According to Avogadro's Law, same volume of any gas at standard temperature (273.15 K or O °C) and pressure (1 atm) will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).

Data Given:

n = moles = <u>???</u>

V = Volume = 87.6 L

Solution:

As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain....

= ( 1 mole × 87.6 L) ÷ 22.4 L

= 3.91 moles

<h3>2nd Method:</h3>

Assuming that the gas is acting ideally, hence, applying ideal gas equation.

P V = n R T ∴ R = 0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹

Solving for n,

n = P V / R T

Putting values,

n = (1 atm × 87.6 L)/(0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹ × 273.15K)

n = 3.91 moles

Result:

87.6 L of Neon gas will contain 3.91 moles at standard temperature and pressure.

7 0

2 years ago

What is the relationship between frequency and wavelength?

IrinaVladis [17]

Answer:

frequency it the measure of the wave length. The measure of the peaks and troughs is how you measure the frequency. the distance between these is the wave length.

6 0

2 years ago

A 2.684-g sample of zinc oxide was reduced by hydrogen gas, resulting in 2. 156 g of pure zinc metal. Determine the empirical fo

Afina-wow [57]

The empirical formula of the initial zinc oxide is ZnO.

<h3>What is Empirical Formula?</h3>

The empirical formula of a compound represents the ratios of elements in a compound but not the actual numbers or arrangement of the atoms.

It is the lowest whole number ratio of the element in the compound.

<h3>How to find out the empirical formula?</h3>

Find out the given masses and molar masses of the elements

The molar mass of Zn = 65 gmol⁻¹

Given the mass of Zn = 2.156 g

The molar mass of Oxygen = 16 gmol⁻¹

The mass of Oxygen = Mass of a sample of zinc oxide - the mass of zinc metal

= (2.684 - 2.156) g

= 0.528 g

Find the number of moles of the elements in the compound

The number of moles is given by

$n = \frac{m}{M}$

where m = given mass and

M = Molar mass

Number of moles of Zinc = $\frac{2.156}{65}$ = 0.033 moles

Number of moles of Oxygen = $\frac{0.528}{16}$ = 0.033 moles

Find the simplest ratios of the elements in the compound. To find the ratios simply divide the number of moles by the lowest number of moles obtained.

Here, the number of moles is the same for both elements. Hence, the simplest ratio for Zn:O is 1:1.

Therefore, the empirical formula of zinc oxide is ZnO.

Learn more about the empirical formula:

brainly.com/question/1603500

#SPJ4

5 0

1 year ago