Answer:
CH3 - CH2 - NH - C(CH3)3
Explanation:
The 1HNMR is the acronym for Proton nuclear magnetic resonance and it is used in chemistry or Chemical laboratory for the analysis and identification of compounds.
In order to be able to answer the question accurately you have to have the tables containing all the values for chemical shift. The Chemical shift is measured in ppm and it occur due to Resonance frequency variation.
From the table, a singlet at 1.15 ppm (9H) is - C(CH3)3.
A singlet at d 0.9 ppm (1H) shows the presence of a secondary amine group, that is -R2NH group.
A triplet at 1.10 ppm (3H) shows that we have;
CH3- CH2-
A quartet at 2.6 ppm (2H) shows that we have;
-CH2 - CH3.
Therefore, joining all together we have;
CH3 - CH2 - NH - C(CH3)3.
Kindly check attached file for the picture of the structure.
Answer:
Average atomic mass of carbon = 12.01 amu.
Explanation:
Given data:
Abundance of C¹² = 98.89%
Abundance of C¹³ = 1.11%
Atomic mass of C¹² = 12.000 amu
Atomic mass of C¹³ = 13.003 amu
Average atomic mass = ?
Solution:
Average atomic mass of carbon = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass of carbon = (12.000×98.89)+(13.003×1.11) /100
Average atomic mass of carbon= 1186.68 + 14.43333 / 100
Average atomic mass of carbon = 1201.11333 / 100
Average atomic mass of carbon = 12.01 amu.
In chemistry<span>, a </span>salt<span> is an ionic compound that can be formed by the neutralization reaction of an acid and a base.So yes it is</span>
Answer:
<em><u>To determine the number of significant figures in a number use the following 3 rules:</u></em>
<em><u>To determine the number of significant figures in a number use the following 3 rules:Non-zero digits are always significant.</u></em>
<em><u>To determine the number of significant figures in a number use the following 3 rules:Non-zero digits are always significant.Any zeros between two significant digits are significant.</u></em>
<em><u>To determine the number of significant figures in a number use the following 3 rules:Non-zero digits are always significant.Any zeros between two significant digits are significant.A final zero or trailing zeros in the decimal portion ONLY are significant.</u></em>
Answer:
56 g of sucrose is the mass needed
Explanation:
Formula for osmotic pressure → π = M . R . T
8 atm = M . 0.082 L.atm/mol.K . 290 K
8 atm / (0.082 L.atm/mol.K . 290 K) = M → 0.336 mol/L
Let's determine the mass of sucrose that represents 0.336 mol
0.336 mol . 342 g / 1mol = 114.9 g
This is the mass that corresponds to 1L of solution, but we have 0.488 L
Solution density = 1 g/mL → 488 g are contained in 488 mL.
488 mL . 1L / 1000 mL = 0.488 L
Let's make a rule of three:
1L is the volume for 114.9 g of sucrose
In 0.488 L of volume, we need a mass of (0.488L . 114.9 g) 1L = 56 g
