There are 22 bonding parts
Answer:
(a) 0.25 mol
(b) 0.11 mol
(c) 8.77 mol
Explanation:
(a)
We use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 1.00 atm
V = Volume of the gas = 6.0 L
T = Temperature of the gas = 298 K
R = Gas constant =
n = number of moles = ?
Putting values in above equation, we get:
![1.00 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1.00\times 6.0}{0.0821\times 298}=0.25mol](https://tex.z-dn.net/?f=1.00%20atm%5Ctimes%206.0L%3Dn%5Ctimes%200.0821%5Ctext%7B%20L.atm%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D%5Ctimes%20298K%5C%5C%5C%5Cn%3D%5Cfrac%7B1.00%5Ctimes%206.0%7D%7B0.0821%5Ctimes%20298%7D%3D0.25mol)
(b)
We use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 0.296 atm
V = Volume of the gas = 6.0 L
T = Temperature of the gas = 200 K
R = Gas constant =
n = number of moles = ?
Putting values in above equation, we get:
![0.296 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 200K\\\\n=\frac{0.296\times 6.0}{0.0821\times 200}=0.11mol](https://tex.z-dn.net/?f=0.296%20atm%5Ctimes%206.0L%3Dn%5Ctimes%200.0821%5Ctext%7B%20L.atm%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D%5Ctimes%20200K%5C%5C%5C%5Cn%3D%5Cfrac%7B0.296%5Ctimes%206.0%7D%7B0.0821%5Ctimes%20200%7D%3D0.11mol)
(c)
We use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 30 atm
V = Volume of the gas = 6.0 L
T = Temperature of the gas = 250 K
R = Gas constant =
n = number of moles = ?
Putting values in above equation, we get:
![30 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 250K\\\\n=\frac{30\times 6.0}{0.0821\times 250}=8.77mol](https://tex.z-dn.net/?f=30%20atm%5Ctimes%206.0L%3Dn%5Ctimes%200.0821%5Ctext%7B%20L.atm%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D%5Ctimes%20250K%5C%5C%5C%5Cn%3D%5Cfrac%7B30%5Ctimes%206.0%7D%7B0.0821%5Ctimes%20250%7D%3D8.77mol)
Complete Question
The complete question is shown on the first uploaded image
Answer:
Answer: 760 uM
Explanation:
the addition of solvent to a solution in a such away that the volume of the solution increases and the concentration decreases is a process know as dilution
The concentration and the volume of the dilute and concentrated solution are given below as follows
![= C_{f}V_{f}](https://tex.z-dn.net/?f=%3D%20C_%7Bf%7DV_%7Bf%7D)
Concentrated solution Dilute solution
Given that M1 = 97.0uM
V1 = 47.0 mL
V2 = 6.0 mL
M2 = ?
Therefore M1V1 = M2V2
M2 = M1V1/V2
M2 = (97*47)/6
M2 = 760 uM
Answer: 760 uM
Use the following equation:
Given # of moles * molar mass (g) per mol = Mass (g)
This gives us 11.9 x <span> 51.9962 (g) per mol.
618.75 moles</span>
Answer: Option C) 9.5
Explanation:
Given that,
pOH of solution = ?
pH of solution = 4.5 (it is an acidic solution because any pH values less than 7.0 is said to be acidic)
Recall that pH is the negative logarithm of hydrogen ion concentration in the solution while pOH is the negative logarithm of hydroxide ion concentration in the solution.
Hence, pH + pOH = 14
4.5 + pOH = 14
pOH = 14 - 4.5
pOH = 9.5
Thus, the pOH of the same solution is 9.5