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PilotLPTM [1.2K]
3 years ago
10

I need to solve for X Y and Z please and thank you

Mathematics
1 answer:
erastovalidia [21]3 years ago
4 0

9514 1404 393

Answer:

  • x = 5
  • y = 30
  • z = 8

Step-by-step explanation:

The rhombus has several relevant properties.

  • The sides are all the same length
  • Diagonals are perpendicular bisectors of each other
  • Diagonals divide the rhombus into congruent triangles

The last of these relations can be used to find x:

  7x° = 35°

  x = 35°/7° = 5

The second of the relations can be used to find y:

  3y° = 90°

  y = 90°/3° = 30

The first of the relations can be used to find z:

  10z -8 = 5z +32

  5z = 40 . . . . . . . . . add 8-5z

  z = 40/5 = 8

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The answer is c for this
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3 years ago
4n² +7n=0 what do I do if there is no part c?
Gnoma [55]

Answer:

  • Find the coefficients using ax^2 + bx + c = 0

a = 4

b = 7

c = 0

  • Make the coefficient equal 1. But how do we do that? Division.

4n² + 7n = 0

4/4n² + 7n/4 = 0/4

  • Simplify

= n² + 7/4n = 0

a = 1

b = 7/4

c = 0

  • Complete the square using b/2².

b = 7/4

(b/2)² = (7/4 ÷ 2)²

Use fraction rule.

7/4 ÷ 2² = 7/4² / 2²

<em>square the numbers</em>

7/4² / 2² = 49/16 ÷ 4

49/16 ÷ 4 = 49/16 × 1/4

49/16 × 1/4 = 49/64

Add to both sides of the equation using 49/64

b = 7/4

b/2 = 7/4 ÷ 2

<em>simplify</em>

b/2 = 7 ÷ (4 × 2)

<em>simplify(arithmetic)</em>

b/2 = 7/8

n² + 7/4n + 49/64 = 49/64

(n + 7/8)² = 49/64

  • Solve for the unknown x

(n+\frac{7}{8})^2=\frac{49}{64}\\\sqrt{(n+\frac{7}{8})^2}=\sqrt{\frac{49}{64}}\\

Next, cancel out the square on the left side.

n+\frac{7}{8}=+/-\sqrt{\frac{49}{64}}

Subtract 7/8 from both of the sides.

n+\frac{7}{8}-\frac{7}{8}=-\frac{7}{8}+/-\sqrt{\frac{49}{64}}

Simplify the left side.

n=-\frac{7}{8}+/-\sqrt{\frac{49}{64}}\\n=-\frac{7}{8}+/-\frac{\sqrt{49}}{\sqrt{64}}\\n=-\frac{7}{8}+/-\frac{7}{8}\\n_1=0\\n_2=-\frac{7}{4}

<em>That wraps it up for this equation. Hope it helped!</em>

3 0
2 years ago
Solve x2 + 12x = -11 by completing the square. Which is the solution set of the equation?
pogonyaev

Answer:

{-11, -1}

Step-by-step explanation:

x^2 +12x = -11

Take the coefficient of x

12

Divide by 2

12/2 =6

Then square it

6^2 = 36

Add this to both sides

x^2 +12x+36 = -11+36

(x+6)^2 = 25

Take the square root of each side

sqrt((x+6)^2) = ± sqrt(25)

x+6 = ± 5

Separate into two equations

x+6 = 5           x+6=-5

Subtract 6 from each side

x+5-6 = 5-6          x+6-6 = -5-6

x=-1                              x=-11

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