If the care is impacted by something over 25 miles per hour
Answer:
My guess is b or c but its robably wrong
Explanation:
I just also need points sorry <3
I believe the statement above is true. The stronger the wind, the larger the particles it erodes<span>. The stronger the wind, the larger the particles that are carried away.
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Answer:
Ksp = 2.74 x 10⁻⁵
Explanation:
The solubility equilibrium for Ca(OH)₂ is the following:
Ca(OH)₂(s) ⇄ Ca²⁺(aq) + 2 OH⁻(aq)
I 0 0
C + s + 2s
E s 2s
According to the ICE table, the expression for the solubility product constant (Kps) is:
Ksp = [Ca²⁺] x ([OH⁻])² = s x (2s)² = 4s³
Then, we calculate Ksp from the solubility value (s):
s = 0.019 M
⇒ Ksp = 4s³ = 4 x (0.019)³ = 2.74 x 10⁻⁵