Answer:
3.481 x 10²⁴ atoms
Explanation:
Data Given:
Number of moles of NH₄NO₃ = 5.78 mol
Number of atoms of NH₄NO₃ = ?
Solution:
Formula used
no. of moles = no. of atoms / Avogadro's number
As we have to find no. of atoms
So, we have to rearrange the above equation
no. of atoms = no. of moles x Avogadro's number . . . . . (1)
Where
Avogadro's number = 6.022 x 10²³ atoms
Put values in above Equation 1
no. of atoms = 5.78 mol x 6.022 x 10²³ atoms/mol
no. of atoms = 3.481 x 10²⁴ mol
So,
no. of atoms in 5.78 mole NH₄NO₃ = 3.481 x 10²⁴ atoms
Explanation:
please write correct answer
Answer:
B
Explanation:
so you started out with 80
you have to cool it till 60
so it is decreasing which means you have to subtract
Note=if something is increasing or wanting to go up its addition but for this problem 60 is less then 80 so we are doing subtraction
80-60=20
Answer:
20.2 amu.
Explanation:
Let A represent isotope ²⁰X
Let B represent isotope ²²X
From the question given above, the following data were obtained:
For Isotope A (²⁰X):
Mass of A = 20
Abundance (A%) = 90%
For Isotope B (²²X):
Mass of B = 22
Abundance (A%) = 10%
Relative atomic mass (RAM) =?
The relative atomic mass (RAM) of the element can be obtained as follow:
RAM = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
RAM = [(20 × 90)/100] + [(22 × 10)/100]
RAM = 18 + 2.2
RAM = 20.2 amu
Thus, relative atomic mass (RAM) of the element is 20.2 amu
