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shtirl [24]
3 years ago
15

Write the equation of the function f(x) = a·b^x when f(1) = 12 and f(3) = 27.

Mathematics
1 answer:
zloy xaker [14]3 years ago
7 0

Answer:

8*(3/2)^x =f(x)

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20 POINTS for anyone that can help!
ANTONII [103]

Answer:

ABCD is a square and a rectangle, just graph the points to see the shape it makes

4 0
3 years ago
Please help me in this question
Marrrta [24]

Answer:

option c

Step-by-step explanation:

option c is right..

3 0
3 years ago
Complex numbers zj and zz are given by zj = 3- j2, zz = - 4 + j3. (a) express zj and zz in polar form. (b) find lz1l by first ap
inna [77]

Solution:

Given: zj = 3- j2, zz = - 4 + j3

Part a:

zj = 3- j2 = 3.6e^{-j33.7^{\circ}}

zz = - 4 + j3 = 5e^{j143.1^{\circ}}

Part b:

|zj| = |3− j2| =  √3² +(−2)² = √13 = 3.60

|z1| =  √(3− j2)(3+ j2) = √ 13 = 3.60.

Part c:

With the help of part a:

z1z2 = 3.6e^{-j33.7^{\circ}}.5e^{j143.1^{\circ}}

6 0
3 years ago
Which theorem or postulate proves that △ABC and △DEF are similar?
yan [13]

Answer:

△ABC and △DEF are similar by SAS Similarity Theorem.

Option (C) is correct .

Step-by-step explanation:

Definition of SAS Similarity property

Two triangles are said to be similar by SAS Similarity property If two sides are proportional and one corresponding angle congruent .

In △ABC and △DEF

\frac{ED}{AB}= \frac{7}{21}

\frac{ED}{AB}= \frac{1}{3}

and

\frac{EF}{BC}= \frac{11}{33}

\frac{EF}{BC}= \frac{1}{3}

Thus

\frac{ED}{AB}=\frac{EF}{BC}= \frac{1}{3}

∠ABC = ∠DEF  (As given in the figure )

Thus △ABC and △DEF are similar by SAS Similarity property .

7 0
3 years ago
Read 2 more answers
The rectangle below has an area of 1 8 x 3 18x 3 square meters and a length of 2 x 2 2x 2 meters.
motikmotik

Answer:

\text{The width of rectangle}=9x\text{ meters}

Step-by-step explanation:

We have been given that the rectangle has an area of 18x^3 square meters and a length of 2x^{2}. We are asked to find the width of rectangle.

Since we know that area of a rectangle is width times length of the rectangle, so we can find width of our given rectangle by dividing given area by length of rectangle.

\text{Area of rectangle}=\text{Width of rectangle *Length of the rectangle}

\frac{\text{Area of rectangle}}{\text{Length of rectangle}}=\frac{\text{Width of rectangle *Length of the rectangle}}{\text{Legth of rectangle}}

\text{The width of rectangle}=\frac{\text{Area of rectangle}}{\text{Length of rectangle}}

Upon substituting our given values in above formula we will get,

\text{The width of rectangle}=\frac{18x^3\text{ meter}^2}{2x^2\text{ meters}}

\text{The width of rectangle}=\frac{9x^3\text{ meters}}{x^2}

Using exponent rule for quotient \frac{a^m}{a^n}=a^{m-n} we will get,

\text{The width of rectangle}=9x^{3-2}\text{ meters}

\text{The width of rectangle}=9x^{1}\text{ meters}=9x\text{ meters}

Therefore, width of our given rectangle will be 9x meters.

3 0
3 years ago
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