Question

How many moles of electrons are required to reduce one mole of oxygen gas (O2) to two moles of oxygen ions (O2-)?

Answer 1

O₂ + 4e⁻ ------> 2O²⁻

:)

Answer 2

Answer:

The correct answer is 4 electrons.

Explanation:

Reduction reaction is defined as chemical reaction in which element gains electrons and it get reduced. Also oxidation state of that element also deceases.

$O_2+e^-\rightarrow 2O^{2-}$

Charge on both sides should be balanced so for that write 4 as a coefficient of en electron in an above reaction.By this the charge on booth sides becomes (4-).

$O_2+4e^-\rightarrow 2O^{2-}$

1 mole of oxygen gas gets reduced by 4 electrons into 2 moles of oxygen  ions.