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2 years ago

How many moles of electrons are required to reduce one mole of oxygen gas (O2) to two moles of oxygen ions (O2-)?

Chemistry

2 answers:

sergey [27]2 years ago

7 0

O₂ + <u>4e⁻ </u>------> 2O²⁻

:)

mafiozo [28]2 years ago

6 0

Answer:

The correct answer is 4 electrons.

Explanation:

Reduction reaction is defined as chemical reaction in which element gains electrons and it get reduced. Also oxidation state of that element also deceases.

$O_2+e^-\rightarrow 2O^{2-}$

Charge on both sides should be balanced so for that write 4 as a coefficient of en electron in an above reaction.By this the charge on booth sides becomes (4-).

$O_2+4e^-\rightarrow 2O^{2-}$

1 mole of oxygen gas gets reduced by 4 electrons into 2 moles of oxygen ions.

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An electric kettle draws a current of 6.50 A while it is plugged into a 120-V

Umnica [9.8K]

Answer:

780 watts

Explanation:

formula to find power when given amps and voltage

P = A x V

=6.50a x 120V

= 780 W (watts)

7 0

2 years ago

The density of ethanol is 0.788 g/mL. What is the mass of 157 mL of alcohol?

Lina20 [59]

Answer:

<h3>The answer is 123.72 g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 157 mL

density = 0.788 g/mL

We have

mass = 0.788 × 157 = 123.716

We have the final answer as

Hope this helps you

6 0

2 years ago

Scientist have genetically altered a common virus so that it can Destroy the most lethal type of brain tumor without harming the

sergey [27]

Answer:

The correct answer is - discovering or diagnosing the disease.

Explanation:

According to the question, this technology includes genetically modifying a common virus in order to destroy or kill the deadly brain tumor without affecting normal cells around the tumor, this technique is genetic engineering.

This technique can help in treating or curing the disease by killing the tumor cells and make them non-lethal. It can also prevent the tumor cells to grow and make them controlled. There is nothing mention related to diagnosing the disease in the question and it is not possible to find this tumor with help of such a technique.

3 0

2 years ago

If 31.6 g of KMnO4 is dissolved in enough water to give 160 mL of solution, what is the molarity?

Zina [86]

Answer:

A. 1.25M

B. 19.98g

Explanation:

A. Data obtained from the question include the following:

Mass of KMnO4 = 31.6 g

Volume = 160 mL

Molarity =..?

We'll begin by calculating the number of mole KMnO4 in the solution. This is can be obtained as follow:

Mass of KMnO4 = 31.6 g

Molar mass of KMnO4 = 39 + 55 + (16x4) = 158g/mol

Number of mole of KMnO4 =..?

Mole = mass /Molar mass

Number of mole of KMnO4 = 31.6/158 = 0.2 mole

Now, we can obtain the molarity of the solution as follow:

Volume = 160 mL = 160/1000 = 0.16L

Mole of KMnO4 = 0.2 mole

Molarity = mole /Volume

Molarity = 0.2/0.16 = 1.25M

B. Data obtained from the question include the following:

Volume = 300mL

Molarity = 0.74 M

Mass of H2C2O4 =..?

First, we shall determine the number of mole H2C2O4. This is illustrated below:

Volume = 300mL = 300/1000 = 0.3L

Molarity = 0.74 M

Mole of H2C2O4 =?

Mole = Molarity x Volume

Mole of H2C2O4 = 0.74 x 0.3

Mole of H2C2O4 = 0.222 mole

Now, we can easily find the mass of H2C2O4 by converting 0.222 mole to grams as shown below:

Number of mole of H2C2O4 = 0.222 mole

Molar mass of H2C2O4 = (2x1) + (12x2) + (16x4) = 2 + 24 + 64 = 90g/mol

Mass of H2C2O4 =..?

Mass = mole x molar mass

Mass of H2C2O4 = 0.222 x 90

Mass of H2C2O4 = 19.98g

5 0

3 years ago

Select all the correct answers.

stich3 [128]

Answer : The products of the acid-base reaction between $HClO_3$ and LiOH are, $LiClO_3$ and $H_2O$

Explanation :

Neutralization reaction : It is a type of chemical reaction in which an acid react with a base to give salt and water as a product that means it reacts to give a neutral solution. It is also known as acid-base reaction.

The acid-base reaction will be:

$HClO_3+LiOH\rightarrow LiClO_3+H_2O$

Therefore, the products of the acid-base reaction between $HClO_3$ and LiOH are, $LiClO_3$ and $H_2O$

6 0

3 years ago

Read 2 more answers