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3 years ago

How many moles of electrons are required to reduce one mole of oxygen gas (O2) to two moles of oxygen ions (O2-)?

Chemistry

2 answers:

sergey [27]3 years ago

7 0

O₂ + <u>4e⁻ </u>------> 2O²⁻

:)

mafiozo [28]3 years ago

6 0

Answer:

The correct answer is 4 electrons.

Explanation:

Reduction reaction is defined as chemical reaction in which element gains electrons and it get reduced. Also oxidation state of that element also deceases.

$O_2+e^-\rightarrow 2O^{2-}$

Charge on both sides should be balanced so for that write 4 as a coefficient of en electron in an above reaction.By this the charge on booth sides becomes (4-).

$O_2+4e^-\rightarrow 2O^{2-}$

1 mole of oxygen gas gets reduced by 4 electrons into 2 moles of oxygen ions.

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How do I do this? What are the answers to the 5 questions shown?

frozen [14]

Answer:

1. C₃H₆O₃

2. C₆H₁₂

3. C₆H₂₄O₆

4. C₆H₆

5. N₂O₄

Explanation:

1. Determination of the molecular formula.

Empirical formula => CH₂O

Mass of compound = 90 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[CH₂O]ₙ = 90

[12 + (2×1) + 16]n = 90

[12 + 2 + 16]n = 90

30n = 90

Divide both side by 30

n = 90/30

n = 3

Molecular formula = [CH₂O]ₙ

Molecular formula = [CH₂O]₃

Molecular formula = C₃H₆O₃

2. Determination of the molecular formula.

Empirical formula => CH₂

Mass of compound = 84 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[CH₂]ₙ = 84

[12 + (2×1)]n = 84

[12 + 2]n = 84

14n = 84

Divide both side by 14

n = 84/14

n = 6

Molecular formula = [CH₂]ₙ

Molecular formula = [CH₂]₆

Molecular formula = C₆H₁₂

3. Determination of the molecular formula.

Empirical formula => CH₄O

Mass of compound = 192 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[CH₄O]ₙ = 192

[12 + (4×1) + 16]n = 192

[12 + 4 + 16]n = 192

32n = 192

Divide both side by 32

n = 192/32

n = 6

Molecular formula = [CH₄O]ₙ

Molecular formula = [CH₄O]₆

Molecular formula = C₆H₂₄O₆

4. Determination of the molecular formula.

Empirical formula => CH

Mass of compound = 78 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[CH]ₙ = 78

[12 + 1]n = 78

13n = 78

Divide both side by 13

n = 78/13

n = 6

Molecular formula = [CH]ₙ

Molecular formula = [CH]₆

Molecular formula = C₆H₆

5. Determination of the molecular formula.

Empirical formula => NO₂

Mass of compound = 92 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[NO₂]ₙ = 92

[14 + (2×16)]n = 92

[14 + 32]n = 92

46n = 92

Divide both side by 46

n = 92/46

n = 2

Molecular formula = [NO₂]ₙ

Molecular formula = [NO₂]₂

Molecular formula = N₂O₄

6 0

3 years ago

How many hydrogen atoms are in 2.30 mol of ammonium sulfide

vazorg [7]

1] Find out how many moles

2] Use Avagadro's number to find number of molecules

1] [2.3 g (NH4)2SO4] x [1 mol (NH4)2SO4] / [132.14g(NH4)2SO4 )] = 0.017406 moles (NH4)2SO4

2] 0.017406 moles x 6.022 x 10^23 molecules/mole = 1.05 x 10^21 molecules (NH4)2SO4

3 0

4 years ago

Read 2 more answers

Balance the following chemical equations:

irakobra [83]

Hey there!

N₂ + H₂ → NH₃

Balance N.

2 on the left, 1 on the right. Add a coefficient of 2 in front of NH₃.

N₂ + H₂ → 2NH₃

Balance H.

2 on the left, 6 on the right. Add a coefficient of 3 in front of H₂.

N₂ + 3H₂ → 2NH₃

This is our final balanced equation:

N₂ + 3H₂ → 2NH₃

Hope this helps!

8 0

4 years ago

Read 2 more answers

_____ bonds share electron pairs. Ionic Metallic Hydrogen Covalent

IceJOKER [234]

Covalent bonds- are bonds that share electron pairs between atoms.

Ionic bonds are bonds that are made after one atom GIVES AWAY one or more electrons to the other atom.

Hydrogen Bonds- bonds between hydrogen(H) and usually O,N, or F. Hydrogen bonds are NOT TRUELY BONDS they are an ELECTROMAGNETIC ATTRACTIONS. These bonds can be Intramolecular(bonds within a molecule) or Intermolecular bonds (between two separate molecules). Individually a hydrogen bond is weak. However, hydrogen bonds can be strong in large numbers.

Metallic Bonding- occurs when metals bond with other metals their valence electrons become "delocalized," or free to move around. This delocalization forms something called the electron sea. In the electron sea, valence electrons DO NOT BELONG TO ANYONE ATOM.

Therefore, the answer is Covalent bonds.
Hope this helped! :)

7 0

3 years ago

How much heat (in kilojoules) is evolved or absorbed in the reaction of 1.90g of Na with H2O ?

irina1246 [14]

The heat of the reaction is an extensive property: it is proportional to the quantity of the quantity that reacts.

The change in enthalpy is a measured of the heat evolved of absorbed.

When the heat is released, the change in enthalpy is negative.

The reaction of 2 moles of Na develops 368.4 kj of energy.

Calculate the number of moles of Na in 1.90 g to find the heat released when this quantity reacts.

Atomic mass of Na: 23 g/mol

#mol Na = 1.90 g / 23 g/mol = 0.0826 mol

Do the ratios: [368.4 kj/2mol ] * 0.0826 mol = 15.21 kj.

Then the answer is that 15.21 kj of heat is released (evolved)

6 0

3 years ago