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saul85 [17]
3 years ago
5

How many moles of electrons are required to reduce one mole of oxygen gas (O2) to two moles of oxygen ions (O2-)?

Chemistry
2 answers:
sergey [27]3 years ago
7 0
O₂ + <u>4e⁻ </u>------> 2O²⁻

:)
mafiozo [28]3 years ago
6 0

Answer:

The correct answer is 4 electrons.

Explanation:

Reduction reaction is defined as chemical reaction in which element gains electrons and it get reduced. Also oxidation state of that element also deceases.

O_2+e^-\rightarrow 2O^{2-}

Charge on both sides should be balanced so for that write 4 as a coefficient of en electron in an above reaction.By this the charge on booth sides becomes (4-).

O_2+4e^-\rightarrow 2O^{2-}

1 mole of oxygen gas gets reduced by 4 electrons into 2 moles of oxygen  ions.

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Temka [501]

Answer:

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Explanation:

The chemical balanced equation is;

2Ca + O₂ → 2CaO

The ratio of calcium(Ca) to Calcium Oxide(Cao) in this equation is 2:2.

Now, when 3 moles of calcium react with oxygen, Cao produced will be;

3 moles of O₂ × 2 moles of CaO/2 moles of Cao = 3 moles of CaO

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Answer:

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3 years ago
If I have 251.14 grams of citric acid and calcium bicarbonate mixture how much citrus acid do I have??
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Water is<br> A. Acidic<br> B. Basic<br> C. Neutral
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