Raoult's law is stated as<span> the partial </span>vapor pressure<span> of each component in the </span> mixture<span> of ideal liquids is equal to the vapor pressure of the pure component multiplied by its </span>mole fraction<span> in the mixture. Mathematically, it is expressed as
P = Xi Pi
where P= vapor pressure of solution
Xi = mole fraction of i component
Pi = vapor pressure of pure i component.
In present case, P1 = 0.459 atm and n1 = number of mole of ethanol = 0.090
n2 = number of mole of </span><span> naphthalene = 0.01
</span>∴ Mole fraction of ethanol =
=
= 0.9
Thus, vapor pressure of solution = 0.9 X 0.459 = 0.4131 atm.
Answer: <span>The vapor pressure of pure ethanol at 60 °c is 0.459 atm. Raoult's law predicts that a solution prepared by dissolving 10.0 mmol naphthalene (nonvolatile) in 90.0 mmol ethanol will have a vapor pressure of
0.4131 atm.</span>
ENERY AND FORCE AND OUT AND IN
Answer:
. A sample of hydrogen has a volume of 65.0 mL at a pressure of 0.992 atm and a temperature of 16°c. What volume will the hydrogen occupy at 0.984 atm and 25°c? 2. A sample of nitrogen collected in the laboratory occupies a volume of 725 mL at a pressure of 0.971 atm. What volume will the gas occupy at a pressure of 1.40 atm, assuming the ...
Explanation:
Answer:
Nicotinamide adenine dinucleotide
Flavin adenine dinucleotide
Explanation:
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