Answer:
carbonyl (-C=O)
hydroxyl (-OH)
Explanation:
Sugars have a carbonyl group that interacts with an hydroxyl group that forms a ring structure when the dry molecule is placed in water. Let take a look at sucrose for example.
Sucrose have the molecular formula of C₁₂H₁₂O₁₁. Its preparation is gotten from a juice of sugar cane. In the process of extracting the juice from sugar cane, the extraction process is done with water usually 80°C. The solution is then treated (purification) afterwards with slaked lime and carbon(iv)oxide. During this stage, the (-C=O) group interfere with the OH group in order to form a ring structure.
Answer:
C.H2O has the highest boiling point.
I am not totally sure.
Hope it help you.
Answer:
In summary, a polar bond results when different atoms share electrons. One atom will attract the bonding electrons more strongly than the other atom and will acquire more than a half share of these electrons. This leaves the other atom with less than a half share and makes the electron distribution unsymmetrical. On a time-average basis the electrons spending more time with one atom and cause it to have a partial negative charge. The other atom, deficient in electrons, acquires a partial positive charge.
Explanation:
The property of a substance to resist the flow of motion is known as viscosity. And, more is the density of a substance more will be its viscosity.
Whereas, lesser is the density of a substance then it is easy for the substance to move.
This means that more is the viscosity of a substance least will be its flow and when a substance has lesser viscosity then it will readily flow from one point to another.
Thus, we can conclude that the viscosities of several liquids are being compared. All the liquids are poured down a slope with equal path lengths. The liquid with the highest viscosity will reach the bottom last.
The metal increases the rate of reaction by providing an alternative pathway with a lower activation energy. this means that more reactant molecules will have energy equal to or greater than the activation energy, hence higher rate of reaction.