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3 years ago

A compound with an empirical formula of C4H4O and a molar mass of 136 g/mol. What is the molecular formula of this compound?

Chemistry

1 answer:

fredd [130]3 years ago

8 0

Answer:

C8H8O2

Explanation:

The molecular formula of a compound is simply a multiple of the empirical formula as shown below:

Molecular formula => [C4H4O]n

From the question given, we were told that molar mass of the compound is 136g/mol. This implies that:

[C4H4O]n = 136

Now, let us find the value of n in order to obtain the desired result. This is illustrated below:

[C4H4O]n = 136

[(12x4) + (4x1) + 16]n = 136

[48 + 4 + 16]n = 136

68n = 136

Divide both side by the coefficient of n i.e 68

n = 136/68

n = 2

Therefore the molecular formula is

=> [C4H4O]n

=> [C4H4O]2

=> C8H8O2

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How can an abiotic factor affect a biotic factor

xenn [34]

Biotic and abiotic factors are the environmental conditions that the organisms have to face to live in a specified environment.

-Abiotic factors-
Abiotic factors are the physical and chemical conditions of an environment. For example : heat, salinity, pressure, light, wind, pH ...

-Biotic factors-
Biotic factors are all the biological conditions of an environment for a specie/taxa. It can include prey and predator abundance, available food amount, available space, intra and interspecific competition...

The development of organims is under the control of abiotic factors. Some are adapted to heat, cold etc ... The abiotic factors will define which organisms are able or not to live in a specified place.

The living organisms will constitute the biotic factors, which define if and how can an organism live in a specified environment.
So, the abiotic factors are controling the biotic factors of an environment.

Hope it helps you !

4 0

3 years ago

A sample of pure NH4HS is placed in a sealed 2.0-L container and heated to 550 K at which the equilibrium constant is 3.5 x 10-3

Zolol [24]

Answer:

The mass of $NH_{3}$ in the container is 2.074 gram

Explanation:

Given:

Volume of $NH_{4} HS$ $V = 2$ lit

Equilibrium constant $k _{eq} = 3.5 \times 10^{-3}$

The reaction in which $NH_{3}$ is produced

$NH_{4} HS$ ⇄ $NH_{3} + H_{2}S$

Here equal moles of $NH_{3}$ and $H_{2}S$ is formed.

From the formula of equilibrium constant,

$k_{eq} = (NH_{3})(H_{2}S )$

$x^{2} = 3.5 \times 10^{-3}$

$x = 0.061$ M

Above value shows,

$NH_{3} = 0.061$ $\frac{moles}{L}$

So in 2 L no. moles of $NH_{3}$ = $0.061 \times 2 = 0.122$ moles.

So mass of 0.122 mole of $NH_{3}$ is = $0.122 \times 17 = 2.074$ g

Therefore, the mass of $NH_{3}$ in the container is 2.074 gram

8 0

3 years ago

Determine how many ml of water you need to remove, by evaporation, if you have a 500 ml of 10.20 M HNO3 dilute solution and you

Ludmilka [50]

The total volume of water that would be removed will be 75 mL

<h3>Dilution equation</h3>

Using the dilution equation:

M1V1 = M2V2

In this case, M1 = 500 mL, V1 = 10.20 M, M2 = 12 M

Substitute:

V2 = 500 x 10.20/12

= 425 mL

The final volume in order to arrive at 12 M HNO3 would be 425 mL from the initial 500 mL. Thus, the total amount of water that will be removed by evaporation can be calculated as:

500 - 425 = 75 mL

More on dilution can be found here: brainly.com/question/7208939

7 0

2 years ago

The specific heat of liquid water is 4.184 j/g· ?c. calculate the energy required to heat 10.0 g of water from 26.5?c to 83.7?c.

Roman55 [17]

Energy required=mass*specific heat*temperature change
=10*4.184*57.2
=2393.248j
=2.39*10^3

5 0

3 years ago

I know that one of them is multiple choice but i’m not sure which one it is.

Evgen [1.6K]

Explanation:

1. neutrons

2. protons

3. protons and neutrons

4. neutrons

5. electrons

I'm not sure with 1 and 4, sorry :<

5 0

2 years ago