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3 years ago

A compound with an empirical formula of C4H4O and a molar mass of 136 g/mol. What is the molecular formula of this compound?

Chemistry

1 answer:

fredd [130]3 years ago

8 0

Answer:

C8H8O2

Explanation:

The molecular formula of a compound is simply a multiple of the empirical formula as shown below:

Molecular formula => [C4H4O]n

From the question given, we were told that molar mass of the compound is 136g/mol. This implies that:

[C4H4O]n = 136

Now, let us find the value of n in order to obtain the desired result. This is illustrated below:

[C4H4O]n = 136

[(12x4) + (4x1) + 16]n = 136

[48 + 4 + 16]n = 136

68n = 136

Divide both side by the coefficient of n i.e 68

n = 136/68

n = 2

Therefore the molecular formula is

=> [C4H4O]n

=> [C4H4O]2

=> C8H8O2

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What is the electron configuration for oxygen with a 2- charge (o2-)?

Juli2301 [7.4K]

Oxygen:
Atomic no. = 8(from periodic table)
⇒1s^2 2s^2 2p^4
But it is O^2-
There are 2 more electrons
=>1s^2 2s^2 2p^6
Voila!

3 0

2 years ago

Aluminum chloride, AlCl3, is an inexpensive reagent used in many industrial processes. It is made by treating scrap aluminum wit

mylen [45]

Answer:

83.8%

Explanation:

The balanced reaction equation is;

2Al(s) + 3Cl2(g) → 2AlCl3(s)

Now we have to obtain the limiting reactant as the reactant that produces the least amount of AlCl3

Amount of Al = 3.11g/27 g/mol = 0.115 moles

If 2 moles of Al yields 2 moles of AlCl3

Then 0.115 moles of Al yields 0.115 moles of AlCl3

For Cl2

Amount of Cl2 = 5.32 g/71 g/mol= 0.075 moles

If 3 moles of Cl2 yields 2 moles of AlCl3

0.075 moles of Cl2 yields 0.075 * 2/3 = 0.05 moles of AlCl3

Hence Cl2 is the limiting reactant

Theoretical yield of AlCl3 = 0.05 moles of AlCl3 * 133g/mol = 6.65 g

%yield = actual yield /theoretical yield * 100

%yield = 5.57 g/6.65 g * 100

%yield = 83.8%

4 0

2 years ago

The person who answerers this will get 100 points pls answer all the question's

zysi [14]

Answer:

I think that is the literal answer

5 0

2 years ago

Mass is measured in ____________, and weight is measured in ______________. A) kilograms, grams B) grams, kilograms C) newtons,

frez [133]

I'm pretty sure the answer is letter D.

8 0

3 years ago

Read 2 more answers

Kerosene, a common space-heater fuel, is a mixture of hydrocarbons whose "average" formula is C₁₂H₂₆.

padilas [110]

The calculated enthalpy of formation of kerosene is 365.4 kJ and heat produced is 78650.3 kJ

For this, we need the normal enthalpy of formation given below

ΔH∘f(CO2)=−393.5kJ/molΔH∘f(H2O)\s=−241.8kJ/molΔH∘f(O2)=0kJ/mol

We shall now determine the enthalpy of kerosene formation:

H rxn = 24 mol H f (CO2) + 26 mol H f (H2O) + 2 mol H f (C12H26) + 37 mol H f (O2) + 1.50 104 kJ = 9444 kJ + 6286.8 kJ + 1500 kJ 2 mol H f (C12H26) = 730.8 kJ H f (C12H26) = 365.4 kJ

Kerosene has a density of 0.74 g/mL.

Kerosene volume (V) equals 0.63 gallons, or 0.63 x 3785.4, or 2384. 8 mL.

We shall now calculate the mass (m) of kerosene:

ρ=mVm\s=ρ×Vm\s=0.749g/mL×2384.mLm\s=1786.2g

We shall now discover the heat that 1786 generated.

Two grams of kerosene

Kerosene's molar mass is 170.33 g/mol.

The mass of two moles of kerosene is equal to 2*170.33*340.66g.

1.50104kJ of heat are generated by 340.66 g of kerosene.

1786 produced heat.

Kerosene 2 grams = 1.50 104 kJ 340.66 1786.2 g = 78650.3 kJ

Learn more about enthalpy here-

brainly.com/question/13996238

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5 0

1 year ago