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3 years ago

The place below earth's surface where the earthquake begins.

Physics

1 answer:

stiv31 [10]3 years ago

8 0

Answer:

The position where an earthquake begins below the earths surface is called the hypo center. The point directly above the hypo center is called the epicenter.

Explanation:

www.usga.gov | United States of America Department of Geological Surveys.

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El tubo de entrada que suministra presión de aire para operar un gato hidráulico tiene 2 cm de diámetro. El pistón de salida es

topjm [15]

Answer:

P₁ = 219.3 Pa

Explanation:

This fluid mechanics problem, we can use that the pressure is distributed with the same value throughout the system, which is Pascal's principle.

Let's use the subinidce1 for the small diameter and the subscript 2 for the larger diameter.

P₁ = P₂

pressure is defined by

P = F / A

we subtitute

F₁ / A₁ = F₂ / A₂

F₁ = F₂ A₁ / A₂

the area in a circle is

A = π r² = π d² / 4

we substitute

F₁ = F₂ (d₁ / d₂)²

we calculate

F₁ = 17640 (2/32)²

F₁ = 68.9 N

Having the force to be applied we can find the air pressure on the small plunger

P₁ = F₁ / A₁

P₁ = F₁ 4 / π d₁²

let's calculate

P₁ = 68.9 4 / (π 0.02²)

P₁ = 219.3 Pa

3 0

3 years ago

A system does 506 kj of work, and loses 266 kj of heat to the surroundings. what is the change in internal energy of the system?

babunello [35]

Answer:

The change in internal energy of the system = -772kJ

Explanation:

Given :

Heat lost by the system , a = -266KJ

Workdone by the system, W = -506KJ

The first law of thermodynamics states that:

Change in internal energy = q + w

Substituting values into the equation

Change in internal energy = (-266KJ) + (-506KJ)

Change in internal energy = -722KJ

7 0

3 years ago

Read 2 more answers

A watt is a unit of light power force motion energy

Crazy boy [7]

The answer would be Power

3 0

3 years ago

500 coulombs of charge flow through a bulb for 25 seconds. Calculate the current trough the bulb.

kondaur [170]

Answer:

500÷25=20

so 20 coulombs per second

please mark me as brainlist

7 0

3 years ago

Two rockets are fired at each other with initial velocities of 150m/s150m/s and are 6000m6000m apart. The first rocket is accele

Nataliya [291]

Answer:

3469.788 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

First rocket

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=150\times t+\frac{1}{2}\times 5\times t^2\\\Rightarrow s=150t+2.5t^2\ m$

Second rocket

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=150\times t+\frac{1}{2}\times 15\times t^2\\\Rightarrow s=150t+7.5t^2\ m$

When this will collide the total distance they would have covered would be 6000 m.

$6000=150t+2.5t^2+150t+7.5t^2\\\Rightarrow 6000=300t+10t^2\\\Rightarrow 10t^2+300t-6000=0$

$t=5\left(\sqrt{33}-3\right),\:t=-5\left(3+\sqrt{33}\right)\\\Rightarrow t=13.72, -43.72$

Hence at 13.72 seconds they will collide assuming they are launched at the same time.

$s=150t+7.5t^2\\\Rightarrow s=150\times 13.72+7.5\times 13.72^2\\\Rightarrow s=3469.788\ m$

The second rocket would have gone 3469.788 m when they collide

7 0

4 years ago