Question

A wagon, initially traveling at a constant 8.2 m/s, starts going down a hill that creates an acceleration of 9.0 m/s2. What is the wagon's velocity 6.6 s after it starts accelerating down the hill?

Answer 1

Answer:

67.6m/s

Explanation:

Given parameters:

Initial velocity  = 8.2m/s

Acceleration  = 9.0m/s²

Time  = 6.6s

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we use the expression below:

     Acceleration  = $\frac{v - u }{t}$

v is the final velocity

u is the initial velocity

 t is the time taken

    9  = $\frac{v - 8.2}{6.6}$  

    v - 8.2  = 59.4

    v  = 59.4 + 8.2 = 67.6m/s