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2 years ago

Find the value of a² + b² , when a+ b = 8 and ab = 12

Mathematics

2 answers:

mezya [45]2 years ago

4 0

Answer:

Step-by-step explanation:

6+2=8

6*2=12

$6^{2}$ + $2^{2}$ = 36+4=40

nadezda [96]2 years ago

3 0

Answer:

Here,

$(8) {}^{2} - 2 \times 12$

$64 - 2 \times 12$

$40$

Step-by-step explanation:

So,

Therefore,

$a {}^{2} + b {}^{2} = 40$

I'm not sure if this is correct or not, but this the way I learned..

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Four students draw a design for a class flag. Each flag is black and white. Which designs have the same fractions of black and w

Orlov [11]

Where is the picture

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3 years ago

Explain how double angles compare to parent trigonometric equations

Ne4ueva [31]

Special cases of the sum and difference formulas for sine and cosine yields what is known as the double‐angle identities and the half‐angle identities.

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2 years ago

Lexi said that two lines

omeli [17]

Answer:

Step-by-step explanation:

The easy way to make 2 perpendicular lines is let one be x = 3 and let y = 2.

The third line can be anything that has a minus sign in front of the x. See the graph below. The third line cannot be perpendicular to the other 2.

Sorry, the bottom of the graph got cut off. If you print out the graph and extend the vertical line and the slanted line, you will see how this works.

The three lines are

x = 3
y = 2
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7 0

2 years ago

A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

6 0

2 years ago

PLEASE HELP!!! here are two different strategies to find the new price of a hat after a discount of 40%. The hat was originally

Yakvenalex [24]

Answer:

Step-by-step explanation:

Method 1: Calculate 40% discount on original price, then subtract discount from original price.

Amount of discount = 40% of $30

= 0.40 × $30

= $12

New price = $30 - $12 = $18

Method 2:

New price = (100% - discount percentage) of original price

= 60% of original price

= 0.60 × $30

= $18

6 0

2 years ago