What is the molarity of sulfuric acid if 25.0 ml of the solution is neutralized by 25.5 ml of 0.50 M KOH?
1 answer:
Answer:
[H₂SO₄] = 0.255M
Explanation:
H₂SO₄ + 2KOH => K₂SO₄ + 2H₂O
2(M x V)acid = (M x V)base => M(acid) = (M x V)base /2·Vacid
[H₂SO₄] = (0.5M)(25.5ml)/2(25.0ml) = 0.255M
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