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spayn [35]
3 years ago
10

Which of the following statements does not accurately describe Precambrian Earth?

Chemistry
2 answers:
8_murik_8 [283]3 years ago
6 0

Answer:

C. The ocean water was salty and rich in dissolved oxygen.  

Explanation:

The oldest and longest of the Geological Ages, the Pre-Cambrian extends from the formation of the Earth, approximately 4.5 billion years ago, to 570 million years ago.

This period begins with the formation of the Earth about 4.5 billion years ago, where the Earth was an incandescent mass with rivers of dissolved rock, erupting volcanoes and large amount of sulfur. The atmosphere was initially similar to the atmosphere of Mars and Venus and was composed of nitrogen, ammonia, hydrogen, carbon monoxide, methane and water vapor, expelled by volcanoes, and no sign of oxygen.

After 700 million years, most of the rocks on the surface of the earth had already been cooled and a large amount of water had condensed into an ocean. Even so, the volcanic eruptions were still constant and were giving rise to several islands that were pushed toward each other by the movement of the mantle. In this period small unicellular beings in the ocean begin to appear, the primitive algae and bacteria that assimilate the carbon dioxide of the atmosphere transforming it into free oxygen, slowly changing the composition of the atmosphere that, in that period, was composed basically by nitrogen and steam of Water. They are of this period the oldest fossils of the earth.

Ilya [14]3 years ago
3 0

c. the ocean water was salty and rich in dissolved oxygen

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Explanation:

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Why are coal, oil, and natural gas called fossil fuels?
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Calculate the concentration of formate in a 100mm solution of formic acid at ph 4.15. The pka for formic acid is 3.75
MissTica

The molarity of formic acid is 100 mM or 100\times 10^{-3}M. The dissociation reaction of formic acid is as follows:

HCOOH\leftrightharpoons HCOO^{-}+H^{+}

The expression for dissociation constant of the reaction will be:

K_{a}=\frac{[HCOO^{-}][H^{+}]}{[HCOOH]}

Rearranging,

[HCOO^{-}]=\frac{K_{a}[HCOOH]}{[H^{+}]}

Here, pH of solution is 4.15 thus, concentration of hydrogen ion will be:

[H^{+}]=10^{-pH}=10^{-4.15}=7.08\times 10^{-5}M

Similarly, pK_{a}=3.75 thus,

[K_{a}=10^{-pK_{a}}=10^{-3.75}=1.78\times 10^{-4}M

Putting the values,

[HCOO^{-}]=\frac{(1.78\times 10^{-4}M)(100\times 10^{-3}M)}{(7.08\times 10^{-5}M}=0.2511 M

Therefore, the concentration of formate will be 0.2511 M.

4 0
3 years ago
Cuantos miles de sulfato de calcio están en 60 gramos de sustancia
seropon [69]
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3 years ago
A solution containing 0.102 g of an unknown compound dissolved in 100. mL of water has an osmotic pressure of 28.1 mmHg at 20.°C
IrinaVladis [17]

Answer:

MM = 680g / mol

Explanation:

Hello! To calculate the molar mass of the compound (g / mol), I first have to calculate the molarity.

Molarity can be calculated from the osmotic pressure equation.

op = M * R * T

op = osmotic pressure = 28.1mmHg * (1 atm / 760mmHg) = 0.037atm

M = molarity

R = gas constant

T = temperature (K) = 20 ° C + 273.15 = 293.15K

M (mol / L) = op / R * T

M = 0.037atm / ((0.082 (atm * L) / (K * mol)) * 293.15K) = 0.0015mol / L

As I have the volume = 100ml * (1L / 1000ml) = 0.1L

I can calculate the amount of moles

n = M * V = 0.0015 * 0.1 = 0.00015mol

n = m / MM

m = mass

MM = molar mass

MM = m / n = 0.102g / 0.00015mol

MM = 680g / mol

4 0
3 years ago
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