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Debora [2.8K]
3 years ago
13

In the compounds formed by li, na, k, rb, and cs with chlorine, how many atoms of cl are there per atom of the metal?

Chemistry
1 answer:
egoroff_w [7]3 years ago
5 0
To determine how many chlorine atoms for the compound made from the metals given, we need to know the ionic forms of the metals above. Lithium when in ionic form would have a charge of +1. Sodium metal would have a +1 ionic charge. Potassium would have a charge of +1 as well. Rubidium would have a charge of +1. And Cesium would have +1 also. These metals are located at group 1A so they would all have a +1 charge in the ionic form. To balance this charge, -1 should be paired which would be the charge of a chloride ion. Therefore, for each metal, only 1 chlorine atom would bond.
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When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced. 2 Al ( s ) + 6 HCl ( aq ) ⟶ 2AlCl3 ( aq ) +
Rufina [12.5K]

Answer:

The answer to your question is  V = 19.9 L

Explanation:

Data

mass of Al = 8.60 g

volume of H₂ = ?

Balanced chemical reaction

                 2Al  +  6HCl  ⇒   2AlCl₃  +  3H₂

1.- Use proportions to calculate the mass of H₂ produced

Atomic mass of Al = 2 x 27 = 54 g

Atomic mass of H₂ = 6 x 1 = 6 g

                54 g of Al -------------------- 6 g of H₂

                  8 g  of Al -------------------  x

                  x = (8 x 6) / 54

                  x = 48 / 54

                  x = 0.89 g of H₂

2.- Calculate the volume of H₂

- Convert the H₂ to moles

                    1 g of H₂ --------------- 1 mol

                   0.89 g    ---------------- x

                    x = 0.89 moles

                    1 mol of H₂ -------------- 22.4 l

                   0.89 moles  ------------- x

                    x = (0.89 x 22.4) / 1

                   x = 19.9 L                        

6 0
3 years ago
What is the measure of the efficiency of a chemical reaction? percent yield annual yield actual yield theoretical yield
artcher [175]

Answer:

Precent yield

Explanation:

This is takes into account how much of a substance should have been created (theoretical yield) and compares it to what was actually created (the actual yield).

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7 0
2 years ago
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<span><span>N2</span><span>O3</span><span>(g)</span>→NO<span>(g)</span>+<span>NO2</span><span>(g)</span></span>

<span><span>[<span>N2</span><span>O3</span>]</span> Initial Rate</span>
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We can have the relationship:

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Also, we assume m=1 which is the order of the reaction.

Thus, the relationship is simplified to,

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Answer:

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