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Debora [2.8K]
3 years ago
13

In the compounds formed by li, na, k, rb, and cs with chlorine, how many atoms of cl are there per atom of the metal?

Chemistry
1 answer:
egoroff_w [7]3 years ago
5 0
To determine how many chlorine atoms for the compound made from the metals given, we need to know the ionic forms of the metals above. Lithium when in ionic form would have a charge of +1. Sodium metal would have a +1 ionic charge. Potassium would have a charge of +1 as well. Rubidium would have a charge of +1. And Cesium would have +1 also. These metals are located at group 1A so they would all have a +1 charge in the ionic form. To balance this charge, -1 should be paired which would be the charge of a chloride ion. Therefore, for each metal, only 1 chlorine atom would bond.
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Help out please I really don’t understand these
gavmur [86]
In English

7. Name the elements found in nature in diatomatic form.

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4 0
3 years ago
Using the equations 2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol CO₂ (g) → C(
kkurt [141]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 72 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) 2Sr(s)+O_2(g)\rightarrow 2SrO(s)    \Delta H_1=-1184kJ

(2) SrO(s)+CO_2(g)\rightarrow SrCO_3(s)     \Delta H_2=-234kJ      ( × 2)

(3) CO_2(g)\rightarrow C(s)+O_2(g)     \Delta H_3=394kJ    ( × 2)

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-1184))+(2\times -(-234))+(2\times (394))]=72kJ

Hence, the \Delta H^o_{rxn} for the reaction is 72 kJ.

4 0
3 years ago
A student runs an experiment in the lab and then uses the data to prepare an Arrhenius plot of the natural log of the rate const
Thepotemich [5.8K]

Answer:

21.86582KJ

Explanation:

The graphical form of the Arrhenius equation is shown on the image attached. Remember that in the Arrhenius equation, we plot the rate constant against the inverse of temperature. The slope of this graph is the activation energy and its y intercept is the frequency factor.

Applying the equation if a straight line, y=mx +c, and comparing the given equation with the graphical form of the Arrhenius equation shown in the image attached, we obtain the activation energy of the reaction as shown.

5 0
3 years ago
A car manufacturer needs to assemble the maximum number of cars using the following equation: 1 body frame + 4 wheels + 2 headli
larisa [96]

The wheels will be completely used up and  it is the limiting reactant in this case.

<h3>What is a limiting reactant?</h3>

The limiting reactant is the reactant that is completely used up in a reaction, and thus determines when the reaction stops.

  • 60 breaks will be used for 30 engines and 30 body frame
  • 80 wheels will be used for 20 engines and 20 body frame
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The wheels will be completely used up and  it is the limiting reactant in this case.

Learn more about limiting reactants here: brainly.com/question/14222359

#SPJ1

8 0
2 years ago
Given the following balanced equation, determine the rate of reaction with respect to [SO2].
Gnoma [55]

Answer:

Rate = -1/2 Δ[SO<sub>2</sub>]/Δt

so its gonna be (in more simple terms) rate= -1/2Δ(SO2)/Δt

Explanation:

7 0
2 years ago
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