Formula: % by mass = (mass of solute / mass of solution] *100
Data:
mass of solution = 80.85 g
% by mass = 22.4%
Unknown = mass of solute
Solution
% by mass = (mass of solute / mass of solution] *100 = >
mass of solute = % by mass * mass of solution / 100
mass of solute = 22.4 * 80.85 / 100 = 18.11 g
Answer: 18.11 g
Answer:
enviornmental health perspectives
Explanation:
It matters to the aerodynamics of it because sometimes it's good to have the weight but only if it can take it.
Answer:
The Correct IUPAC name is H3C - CH (CH3) - CH (C2H5) - (CH2)2 - CH3 Class 11
Explanation:
yes searched np is maybe right i not 100% sure i 50% is it right >:) tell if u got it right >:D
We need to keep in mind that the compound is neutral.
H2SO3
2(+1)+S+3(-2)=0 (since its neutral)
2+S-6=0
S-4=0
S=4
Therefore the oxidation number for sulfur is +4.