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3 years ago

How many multiples of 9 are between 100,000 and 100,185 ?

Mathematics

1 answer:

Harrizon [31]3 years ago

7 0

Answer:

Actually, the closest multiples are 100008 and 100185, and when divided by 9, it is from 11112 -> 11131, or 112 -> 131, or 12 -> 31, or 1 ->20

Therefore, there are 20 multiples of 9 between 100,000 and 100,185

Step-by-step explanation:

hope this helps and sorry if i am wrong!!

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Alex needs to varnish the top And the bottom of a dozen rectangular wooden planks planks are 8 feet long and 3 feet wide each pi

meriva

Answer:

It will cost approximately $16.12 to varnish all the wooden planks.

Step-by-step explanation:

We are given the following in the question:

Number of rectangular planks = 12

Dimension of the rectangular wooden plank:

Length = 8 feet

Width = 3 feet

Area covered by I bottle of varnish = 125 Square feet

Cost of 1 bottle of varnish = 3.50 units

Area of 1 rectangular plot =

$A = \text{Length}\times \text{Width}\\A = 8\times 3\\A = 24\text{ square feet}$

Total area to be covered by varnish =

$= \text{Area of 1 plank}\times 12\times \text{Top area and bottom area}\\=24\times 12\times 2\\=576$

Number of varnish bottles required =

$n = \dfrac{\text{Total area}}{\text{Total area covered by 1 varnish bottle}} = \dfrac{576}{125} = 4.608$

Cost of varnishing =

$=\text{Cost of 1bottle of varnish}\times \text{Number of varnish bottles}\\=4.608\times 3.50\\=\$16.12$

Thus, it will cost approximately $16.12 to varnish all the wooden planks.

6 0

3 years ago

Look at the picture and tell me which one it is

zloy xaker [14]

You’re correct it’s the second one

5 0

3 years ago

Read 2 more answers

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Jet001 [13]

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2 years ago

Miriam is picking out some movies to rent, and she is primarily interested in comedies and foreign films. She has narrowed down

Keith_Richards [23]

Answer:

There are 795 combinations.

Step-by-step explanation:

The number of ways or combinations in which we can select k element from a group of n elements is given by:

$nCk=\frac{n!}{k!(n-k)!}$

So, if Miriam want to choose 3 movies with at least two comedies, she have two options: Choose 2 comedies and 1 foreign film or choose 3 comedies.

Then, the number of combinations for every case are:

1. Choose 2 Comedies from the 10 and choose 1 foreign film from 15. This is calculated as:

$10C2*15C1=\frac{10!}{2!(10-8)!}*\frac{15}{1!(15-14)!}$

$10C2*15C1=675$

2. Choose 3 Comedies from the 10. This is calculated as:

$10C3=\frac{10!}{3!(10-3)!}=120$

Therefore, there are 795 combinations and it is calculated as:

675 + 120 = 795

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3 years ago

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mars1129 [50]

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3 years ago