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2 years ago

Why are scientists worried that climate change will cause these toxic algae blooms to become more frequent?

Chemistry

1 answer:

ipn [44]2 years ago

4 0

Answer: Eutrophication is the enhancement of the growth of algae in the water body.

Explanation:

The scientists are worried for the climate change as if the climate changed to prolonged rainy then the frequent raining can remove toxic chemicals from the agricultural sites, landfills, industries, and from other locations and deposit them to the water body (river, lakes, ponds, and others). The deposition of the salts of nitrogen, phosphorus, and sulfur promotes the growth of algae in the water body. This leads to reduction in the concentration of oxygen in the water body. This is called eutrophication. The lack of oxygen can lead to mortality of aquatic animals.

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Which of these pairs of elements have the same number of valence electrons?

photoshop1234 [79]

I need a picture because I don’t know what this is talking about

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2 years ago

What is the difference between docosahexaenoate (DHA) and 19,20-dihydroxydocosapentaenoate (19,20-DHDP)? Only DHA is a polyunsat

andrew11 [14]

Answer:

Explanation:

The correct answer is 19, 20 DHDP is more polar than DHA. This is as a result of the presence of two hydroxyl groups.

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3 years ago

H2(g) + Br2(l) ⇄ 2HBr(g) Kc = 4.8 × 108

elena-14-01-66 [18.8K]

Answer:

1.5 × 10⁻⁹M

Explanation:

1. Equilibrium equation

H₂(g) + Br₂(l) ⇄ 2HBr(g)

2. Equilibrium constant

The liquid substances do not appear in the expression of the equilibrium constant.

$k_c=\dfrac{[HBr(g)]^2}{[H_2]}=4.8\times 10^8M$

3. ICE table.

Write the initial, change, equilibrium table:

Molar concentrations:

H₂(g) + Br₂(l) ⇄ 2HBr(g)

I 0.400 0

C - x +2x

E 0.400 - x 2x

4. Substitute into the expression of the equilibrium constant

$4.8\times 10^8=\dfrac{(2x)^2}{0.400-x}$

5. Solve the quadratic equation

192,000,000 - 480,000,000x = 4x²

x² + 120,000,000x - 48,000,000 = 0

Use the quadratic formula:

$x=\dfrac{-120,000,00\pm\sqrt{(120,000,000)^2-4(1)(-48,000,000}}{2(1)}$

The only valid solution is x = 0.39999999851M

Thus, the final concentration of H₂(g) is 0.400 - 0.39999999851 ≈ 0.00000000149 ≈ 1.5 × 10⁻⁹M

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3 years ago

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2 years ago

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VashaNatasha [74]

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2 years ago