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2 years ago

Why are scientists worried that climate change will cause these toxic algae blooms to become more frequent?

Chemistry

1 answer:

ipn [44]2 years ago

4 0

Answer: Eutrophication is the enhancement of the growth of algae in the water body.

Explanation:

The scientists are worried for the climate change as if the climate changed to prolonged rainy then the frequent raining can remove toxic chemicals from the agricultural sites, landfills, industries, and from other locations and deposit them to the water body (river, lakes, ponds, and others). The deposition of the salts of nitrogen, phosphorus, and sulfur promotes the growth of algae in the water body. This leads to reduction in the concentration of oxygen in the water body. This is called eutrophication. The lack of oxygen can lead to mortality of aquatic animals.

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Calcule la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) que se preparó al mezclar, en un recipiente aforado, 4 mo

oee [108]

Considerando la definición de molaridad, la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) es 0.5 $\frac{moles}{litro}$ .

La molaridad es una medida de la concentración de un soluto en una disolución que se define como el número de moles de soluto que están disueltos en un determinado volumen.

La molaridad de una solución se calcula dividiendo los moles del soluto por el volumen de la solución:

$Molaridad=\frac{numero de moles de soluto}{volumen}$

La Molaridad se expresa en las unidades $\frac{moles}{litro}$ .

En este caso, sabes que una solución acuosa se preparó al mezclar 4 moles del ácido con suficiente agua hasta completar 8 litros de solución. Entonces, sabes que:

número de moles de soluto= 4 moles
volumen= 8 litros

Reemplazando en la definición de molaridad:

$Molaridad=\frac{4 moles}{8 litros}$

Resolviendo:

Molaridad= 0.5 $\frac{moles}{litro}$

Finalmente, la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) es 0.5 $\frac{moles}{litro}$ .

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8 0

2 years ago

……….CO + ………H2 --> C8H18 + ……… H2O

Ksenya-84 [330]

Answer:

8CO + 17H2 = C8H18 + 8H2O

8, 17, 1, 8

5 0

2 years ago

What is the percent error of a length measurement of .454cm if the correct value is 0.546cm?

mina [271]

17% is the percent error

5 0

2 years ago

How many atoms are in 2.3 moles Au?

Vaselesa [24]

Answer:

6.02×10^23atoms of au

6 0

3 years ago

Read 2 more answers

An aqueous solution is listed as being 33.8% solute by mass with a density of 1.15 g/mL, the molar mass of the solute is 145.6 g

vodomira [7]

Answer:

A) 2.69 M

B) 0.059

Explanation:

A) We have:

33.8% solute by mass= 33.8 g solute/100 g solution

molarity = mol solute/ 1 L solution

molarity= $\frac{33.8 g solute}{100 g solution}$ x $\frac{1.15 g solution}{1 ml}$ x $\frac{1 mol solute}{145.6 g solute}$ x $\frac{1000 ml}{1 L}$

molarity= 2.69 mol solute/L solution = 2.69 M

B) We know that there are 33.8 g of solute in 100 g of solution.

As the total solution is compounded by solute+solvent (in this case, solvent is water), the mass of water is the difference between the mass of the total solution and the mass of solute:

mass of water= 100 g - 33.8 g = 66.2 g

Now, we calculate the number of mol of both solute and water:

mol solute= 33.8 g solute x $\frac{1 mol solute}{145.6 g}$ = 0.232 mol

mol H20= 66.2 g H₂O x $\frac{1 mol H2O}{18 g}$

Finally, the mol fraction of solute (Xsolute) is calculated as follows:

Xsolute= $\frac{mol solute}{total mol}= \frac{mol solute}{mol solute + mol H2O}=\frac{0.232 mol}{0.232 mol + 3.677 mol}$

Xsolute= 0.059

4 0

2 years ago