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adoni [48]
3 years ago
9

What happens to the average kinetic energy of the molecules of a warm substance when the temperature of the substance is slightl

y decreased? (5 points) Group of answer choices It increases. It decreases. It becomes zero. It remains unchanged.
Chemistry
2 answers:
iris [78.8K]3 years ago
5 0

Answer: Option (b) is the correct answer.

Explanation:

Average kinetic energy is defined as half of mass of gas times the square of root mean square velocity.

Mathematically,    Average K.E = \frac{1}{2}mv^{2}_{rms}

Also,   Kinetic energy = \frac{3}{2}kT

So, when there is increase in temperature then there will be increase in movement of the molecules. As a result, kinetic energy will also increase. Since, kinetic energy is proportional to temperature.

Therefore, with decrease in temperature there will be decrease in average kinetic energy of the molecules.

Thus, we can conclude that the average kinetic energy of the molecules of a warm substance also decreases when the temperature of the substance is slightly decreased.

Ber [7]3 years ago
3 0

Answer:

decreases

Explanation:

the particles have less kinetic energy as the thermal heat is decreased

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A(n)<br> wave carries energy through matter.
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A student has a large number of coins of different diameters, all made by the same metal. She wishes to find the density of the
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Answer:

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6 0
2 years ago
2. 27.8 mL of an unknown were added to a 50.0-mL flask that weighs 464.7 g. The total mass of the flask and the liquid is 552.4
agasfer [191]

Answer:

d=4.24x10^{-4}\frac{lb}{in^3}

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set the equation for the calculation of density and mass divided by volume:

d=\frac{m}{V}

Thus, we can find the mass of the unknown by subtracting the total mass of the liquid to the mass of the flask and the liquid:

m=552.4g-464.7g=87.7g

So that we are now able to calculate the density in g/mL first:

d=\frac{87.7g}{27.8mL}=3.15g/mL

Now, we proceed to the conversion to lb/in³ by using the following setup:

d=3.15\frac{g}{mL}*\frac{1lb}{453.6g}*\frac{1in^3}{16.3871mL}\\\\d=4.24x10^{-4}\frac{lb}{in^3}

Regards!

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2 years ago
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The answer would for sure be 178 because acid & base make that amount so yea!! I’m talllyyy right
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2 years ago
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