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adoni [48]
3 years ago
9

What happens to the average kinetic energy of the molecules of a warm substance when the temperature of the substance is slightl

y decreased? (5 points) Group of answer choices It increases. It decreases. It becomes zero. It remains unchanged.
Chemistry
2 answers:
iris [78.8K]3 years ago
5 0

Answer: Option (b) is the correct answer.

Explanation:

Average kinetic energy is defined as half of mass of gas times the square of root mean square velocity.

Mathematically,    Average K.E = \frac{1}{2}mv^{2}_{rms}

Also,   Kinetic energy = \frac{3}{2}kT

So, when there is increase in temperature then there will be increase in movement of the molecules. As a result, kinetic energy will also increase. Since, kinetic energy is proportional to temperature.

Therefore, with decrease in temperature there will be decrease in average kinetic energy of the molecules.

Thus, we can conclude that the average kinetic energy of the molecules of a warm substance also decreases when the temperature of the substance is slightly decreased.

Ber [7]3 years ago
3 0

Answer:

decreases

Explanation:

the particles have less kinetic energy as the thermal heat is decreased

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A topaz crystal has an interplanar spacing (d) of 1.36 Å (1 Å =1×10^[−10] m). Calculate the wavelength of the X-ray that should
bija089 [108]

Answer:

7.0*10-11m or 70Å

Explanation:

From Bragg's equation, w=2dsinx/n

Since all the parameters are specified in the question, we can easily go ahead to obtain the wavelength but we must convert the spacing given in angstroms to meters using the conversion factor provided as shown in the solution below:

7 0
3 years ago
A person accidentally swallows a drop of liquid oxygen, O2(l), which has a density of 1.149 g/mL. Assuming the drop has a volume
nasty-shy [4]

Answer:

First, let's determine how many moles of oxygen we have.

Atomic weight oxygen = 15.999

Molar mass O2 = 2*15.999 = 31.998 g/mol

We have 3 drops at 0.050 ml each for a total volume of 3*0.050ml = 0.150 ml

Since the density is 1.149 g/mol,

we have 1.149 g/ml * 0.150 ml = 0.17235 g of O2

Divide the number of grams by the molar mass to get the number of moles 0.17235 g / 31.998 g/mol = 0.005386274 mol

Now we can use the ideal gas law. The equation PV = nRT where P = pressure (1.0 atm) V = volume n = number of moles (0.005386274 mol) R = ideal gas constant (0.082057338 L*atm/(K*mol) ) T = Absolute temperature ( 30 + 273.15 = 303.15 K)

Now take the formula and solve for V, then substitute the known values and solve.

PV = nRT V = nRT/P V = 0.005386274 mol * 0.082057338 L*atm/(K*mol) * 303.15 K / 1.0 atm V = 0.000441983 L*atm/(K*) * 303.15 K / 1.0 atm V = 0.133987239 L*atm / 1.0 atm V = 0.133987239 L

So the volume (rounded to 3 significant figures) will be 134 ml.

8 0
3 years ago
Read 2 more answers
Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing tin
mojhsa [17]
  The  half  reactions    as  they  occur   at  each  electrode

is  as  follows

at  the  anode  Sn(s)  =sn^2+(aq)  +  2e  -
at  the  cathode  2  ag^+(aq)   + 2e -  =  2Ag (s)

net  cell  reaction  =   Sn (s)  +  2Ag^+(aq)  =  sn^2+ (aq) +  2  Ag  (s)
8 0
3 years ago
If total pressure of multiple gases is 512 mmHg, and the pressure of oxygen gas is 332 mmHg and the pressure of carbon monoxide
deff fn [24]

Answer: 67 mmHg

Explanation:

According to Dalton's Gas Law, the total pressure of a mixture of gases is the sum of the pressure of each individual gas.

i.e Ptotal = P1 + P2 + P3 + .......

In this case,

Ptotal = 512 mmHg

P(oxygen) = 332 mmHg

P(carbon mono-oxide) = 113 mmHg

Remaining pressure (P3) = ?

To get P3, apply Dalton's Gas Law formula

Ptotal = P(oxygen) + P(carbon mono-oxide) + P3

512 mmHg = 332 mmHg + 113 mmHg + P3

512 mmHg = 445 mmHg + P3

P3 = 512 mmHg - 445 mmHg

P3 = 67 mmHg

Thus, the remaining pressure is 67 mmHg

5 0
3 years ago
Buck's Turf Care Company mowed 233 lawns over a 11 week period. What is the average weekly rate of mowing lawns?
masya89 [10]

Answer: 21 lawns per week

Explanation:

The average weekly rate refers to how many lawns were mowed per week given that 233 were done in 11 weeks.

Rate will be given by;

= Lawns mowed / Weeks taken

= 233 / 11

= 21 lawns per week

6 0
3 years ago
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