Temperature is a(n)<br> ecosystem.<br> component of an ecosystem.

At 1.00 atm and 0 ∘ C, a 5.04 L mixture of methane ( CH 4 ) and propane ( C 3 H 8 ) was burned, producing 15.0 g CO 2 . What was

diamong [38]

Answer : The mole fraction of methane and propane is, 0.742 and 0.26

Explanation :

First we have to calculate the moles of mixture by using ideal gas equation.

PV = nRT

where,

P = pressure of the mixture = 1.00 atm

V = Volume of the mixture = 5.04 L

T = Temperature of the mixture = $0^oC=[0+273]K=273K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles of mixture = ?

Putting values in above equation, we get:

$1.00atm\times 5.04L=n_{mix}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 273K\\n_{mix}=\frac{1.00\times 5.04}{0.0821\times 273}=0.225mol$

Let the number of moles of methane be 'x' moles and that of propane be 'y' moles

So, $x+y=0.225$ .....(1)

The chemical equation for the combustion of methane follows:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

By Stoichiometry of the reaction:

1 mole of methane produces 1 mole of carbon dioxide

So, 'x' moles of methane will produce = $\frac{1}{1}\times x=x$ moles of carbon dioxide

The chemical equation for the combustion of propane follows:

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

By Stoichiometry of the reaction:

1 mole of propane produces 3 mole of carbon dioxide

So, 'y' moles of propane will produce = $\frac{1}{1}\times y=y$ moles of carbon dioxide

Now we have to calculate the mass of carbon dioxide.

Total moles of carbon dioxide = (x + 3y)

Mass of carbon dioxide = (Total moles) × (Molar mass of carbon dioxide)

Molar mass of carbon dioxide = 44 g/mol

Mass of carbon dioxide = $(x+3y)\times 44$

As we are given:

Mass of carbon dioxide = 15.0 g

So, $44(x+3y)=15.0$ .....(2)

Putting value of 'x' from equation 1, in equation 2, we get:

$44(0.225-y+3y)=15.0\\\\0.225+2y=0.341\\\\y=0.058$

Evaluating value of 'x' from equation 1, we get:

$x+0.058=0.225\\x=0.167$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

For Methane:

$\chi_A=\frac{n_A}{n_A+n_B}$

Moles of methane = 0.167 moles

Total moles = 0.225

Putting values in above equation, we get:

$\chi_{(Methane)}=\frac{0.167}{0.225}=0.742$

For Propane:

Moles of propane = 0.058 moles

Total moles = 0.225

Putting values in above equation, we get:

$\chi_{(Propane)}=\frac{0.058}{0.225}=0.26$

Hence, the mole fraction of methane and propane is, 0.742 and 0.26

6 0

4 years ago

The table shows the nature of the reactants and products formed in a certain type of chemical reaction. Nature of Reactants and

Romashka [77]

The given reaction is a double replacement reaction; option B.

<h3>What is a chemical reaction?</h3>

A chemical reaction is a reaction in which chemical changes occurs in the atoms of reactants which results in the formation pf products.

The given reaction is as follows:

Ionic compound + Ionic compound ---> Ionic compound + Ionic compound

Since exchange of ions occur, it is a double replacement reaction.

Learn more about double replacement reaction at: brainly.com/question/5564504

#SPJ1

8 0

2 years ago

The Ksp of barium fluoride, BaF2, is 1.6 x 10-6. A solution of 5.0M NaF is added dropwise to a 2.0L solution that is 0.016 M in

Hatshy [7]

Answer:

Precipitation will occur after the concentration of fluoride ions exceeds 0.01 M.

4 mL volume of NaF must be added to cause $BaF_2$ to precipitate.

Explanation:

Concentration of barium ions = $[Ba^{2+}]=0.016 M$

Volume of barium ion solution = 2.0 L

$BaF_2\rightleftharpoons Ba^{2+}+2F^-$

The solubility product of the barium fluoride = $K_{sp}=1.6\times 10^{-6}$

$K_{sp}=[Ba^{2+}][F^-]^2$

$1.6\times 10^{-6}=[0.016 M]\times [F^-]^2$

$[F^-]=0.01 M$

Precipitation will occur after the concentration of fluoride ions exceeds 0.01 M.

Concentration of fluoride ion = $C_1=0.01 M$

Volume of solution = $V_1=2.0 L$

Concentration of NaF solution added = $C_2=5.0 M$

Volume of NaF solution added = $V_2=?$

$C_1V_1=C_2V_2$

$V_2=\frac{0.01 M\times 2.0 L}{5.0 M}=0.004L$

1 L = 1000 mL

0.004 L = 0.004 × 1000 mL = 4 mL

4 mL volume of NaF must be added to cause $BaF_2$ to precipitate.

3 0

3 years ago

Which of the following statements are true with respect to enzyme activity? Check all that apply. View Available Hint(s) Check a

tiny-mole [99]

Answer: Enzymes speed up the reaction rate.

Enzymes are regenerated when the reaction is completed.

Enzymes affect the reaction pathway by forming an enzyme-substrate complex.

Explanation:

A catalyst is a substance which increases the rate of a reaction by taking the reaction through a different path which involves lower activation energy and thus more molecules can cross the energy barrier and convert to products.

The catalyst itself does not take part in the chemical reaction and is regenerated as such at the end.

Enzymes are biocatalysts and are highly specific in their action. The specificity of enzymes is due to the presence of some specific regions called as active sites. These active sites form weak bonds with substrate molecules.

The specific binding leads to formation of an enzyme substrate complex which accounts for high specificity of enzyme catalyzed reactions.

Once a proper orientation is achieved, substrate molecules react to form products and products leave the enzyme surface as they do not have any affinity towards the enzyme site and are regenerated at the end.

Enzymes work best in optimum temperature and pH range.The enzyme gets denaturated at high pH and temperature.

5 0

4 years ago

HELP PLEASE!!! FIRST PERSON TO ANSWER GETS 90 POINTS AND MARKED BRAINLIEST!

3241004551 [841]

Answer:

MgO has a highest melting point

C5Br has lowesst

Explanation:

It takes a lot of energy to overcome the strong electrostatic forces of attraction between oppositely charged ions, so ionic compounds have high melting and boiling points. ... Magnesium oxide is made from ions with two charges (Mg 2+ and O 2-) and so has a much higher melting point of 2852°C.

3 0

3 years ago

Temperature is a(n) ecosystem. component of an ecosystem.