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Vsevolod [243]
3 years ago
6

CLUES:

Chemistry
1 answer:
Phantasy [73]3 years ago
5 0
5 because it makes sense
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How much heat do you need to raise the temperature of 150 g of ice from -30°C to -15°c?
OLga [1]
To solve this question, you must use the formula: q=mc(change in temperature), where q is heat, m is mass, C is specific heat and temperature change is temperature change. The specific heat for ice is 2.1kJ/Kg x K (given). The change in temperature is 15 degrees Celsius (which you should change to kelvins so you can cancel out units), or 273 + 15 = 288K. The mass is 150 grams, which is 0.15 kg. Now, we can solve for q, heat. We will do this by substituting variables into the formula. After simplifying and cancelling out units, the answer we get is: 90.72kJ.
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3 years ago
If the density of chloroform is 1.5 g/cm³, what is the mass of 50.0 cm³ of chloroform?
Marianna [84]
Density = mass / volume

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hope this helps!
6 0
4 years ago
Read 2 more answers
How many moles are equal to 1.4 x 10^24 atoms of aluminum
Svetlanka [38]

Answer: 2.3 moles

Explanation:

Recall that based on Avogadro's law, 1 mole of any substance has 6.02 x 10^23 atoms

So if 1 mole of Aluminum = 6.02 x 10^23 atoms

Then, Z moles = 1.4 x 10^24 atoms

To get the value of Z, we cross multiply:

1 mole x 1.4 x 10^24 atoms = Z x (6.02 x 10^23 atoms)

1.4 x 10^24 atoms = Z x (6.02 x 10^23)

Hence, Z = (1.4 x 10^24 atoms) ➗ (6.02 x 10^23 atoms)

Z =2.3 moles

Thus, there are 2.3 moles in 1.4 x 10^24 atoms of aluminum.

4 0
4 years ago
An excess of NiCO3, 12 g, was added to 40cm cube of sulpheric acid, 2.0 mol/dm cube. The unreacted nickel carbonate was filtered
Zepler [3.9K]
Calculate the number of moles reacted - 0.08 moles
Calculate the mass of nickel carbonate reacted - 0.08 * 119g
Calculate the mass of unreacted nickel carbonate - 12.0 - (0.08 * 119)g

1 mole of NiCO3 reacts with 1 mole of H2SO4
3 0
3 years ago
0.4 mole of ammonia results after 1.2 mole of nitrogen gas is combined with 1.8 mole of hydrogen gas in a 1.0 L flask. What is t
gavmur [86]

Answer:

Ahhh! I had the same question

Explanation:

4 0
3 years ago
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