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Vsevolod [243]
2 years ago
6

CLUES:

Chemistry
1 answer:
Phantasy [73]2 years ago
5 0
5 because it makes sense
You might be interested in
If I only want to make 500 mL of a 1.25% bleach solution, how many milliliters of bleach would I need? Show your work or explain
kiruha [24]

Answer:

  6.25 mL

Explanation:

1.25% of 500 mL is ...

  0.0125×(500 mL) = 6.25 mL

Since 1.25% of the 500 mL of solution is bleach, that's how much you need. That amount is 6.25 mL.

4 0
2 years ago
For alkyl halides used in SN1 and SN2 mechanisms, rank the leaving groups in order of reaction rate. You are currently in a rank
Alex777 [14]

Answer:

Iodide> Bromide > chloride > flouride

Explanation:

During a nucleophilic substitution reaction, a nucleophilie replaces another in a molecule.

This process may occur via an ionic mechanism (SN1) or via a concerted mechanism (SN2).

In either case, the ease of departure of the leaving group is determined by the nature of the C-X bond. The stronger the C-X bond, the worse the leaving group will be in nucleophilic substitution. The order of strength of C-X bond is F>Cl>Br>I.

Hence, iodine displays the weakest C-X bond strength and it is thus, a very good leaving group in nucleophillic substitution while fluorine displays a very high C-X bond strength hence it is a bad leaving group in nucleophilic substitution.

Therefore, the ease of the use of halide ions as leaving groups follows the trend; Iodide> Bromide > chloride > flouride

4 0
2 years ago
What type of bond would form between aluminum and fluorine?
sesenic [268]

Answer:

I think it would be B

Explanation:

Im sorry if its wrong!!!!!!!

8 0
2 years ago
Chemical formula for sodium and sulfur
Nookie1986 [14]
The chemical formula for sodium and sulfur is Na2S I believe...
8 0
2 years ago
Use the normal boiling points: propane, C3H8, –42.1˚C; butane, C4H10, –0.5˚C; pentane, C5H12, 36.1˚C; hexane, C6H14, 68.7˚C; hep
svlad2 [7]

Answer:

The answer to your question is 126.1°C

Explanation:

                  Boiling point         Difference of boiling points  

C₃H₈             - 42.1°C

C₄H₁₀             -   0.5°C                 41.6 °C

C₅H₁₂               36.1°C                  36.6°C                       41.6 - 36.6 = 5°C          

C₆H₁₄               68.7°C                 32.6°C                        36.6 - 32.6 =4°C

C₇H₁₆               98.4°C                 29.7°C                        32.6 - 29.7 = 2.9°C

We can observe on the table that the difference of boiling points diminishes 1°C when the hydrocarbon has one more carbon, then the difference of temperature between the hydrocarbon of 8 carbons and the hydrocarbon of 7 carbons must be 2°C.

So, this difference is 29.7°C - 2°C = 27.7°C.

And the boiling point of octane is approximately 98.4 + 27.7°C = 126.1°C

7 0
2 years ago
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