Answer:
A) During this procedure ( hypoventilation ) The CO2 in the arterial blood vessels and the lungs increases and this drives the PH level in the system lower, and the equilibrium will shift to the right. this is because the Blood-PH level is controlled by CO2 - bicarbonate buffer system
B) The blood PH may rise to 7.60 during Hyperventilation because the removal of CO2 from the lungs causes the increase in
which is directly proportional to the increase in Blood PH levels
C) Hyper ventilation before a dash would be useful because it will remove excessive Hydrogen ions and and raise the Blood PH levels in preparedness of the production of acids like Lactic acid
Explanation:
A) During this procedure ( hypoventilation ) The CO2 in the arterial blood vessels and the lungs increases and this drives the PH level in the system lower, and the equilibrium will shift to the right. this is because the Blood-PH level is controlled by CO2 - bicarbonate buffer system
⇄ ![H^+ + HCO^-_{3}](https://tex.z-dn.net/?f=H%5E%2B%20%2B%20HCO%5E-_%7B3%7D)
B) The blood PH may rise to 7.60 during Hyperventilation because the removal of CO2 from the lungs causes the increase in
which is directly proportional to the increase in Blood PH levels
C) Hyper ventilation before a dash would be useful because it will remove excessive Hydrogen ions and and raise the Blood PH levels in preparedness of the production of acids like Lactic acid
Answer:
A)The spring scale has a high level of precision and a low level of accuracy.
Explanation:
Hope it works for u guys
Answer:
<h2>0.62 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
![volume = \frac{mass}{density} \\](https://tex.z-dn.net/?f=volume%20%3D%20%20%5Cfrac%7Bmass%7D%7Bdensity%7D%20%5C%5C)
From the question we have
![volume = \frac{3.50}{5.61} \\ = 0.6238859...](https://tex.z-dn.net/?f=volume%20%3D%20%20%5Cfrac%7B3.50%7D%7B5.61%7D%20%20%5C%5C%20%20%3D%200.6238859...)
We have the final answer as
<h3>0.62 mL</h3>
Hope this helps you
Answer: When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is
.
Explanation:
The word equation is given as maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas.
Now, in terms of chemical formulae this reaction equation will be as follows.
![MnO_{2} + HCl \rightarrow H_{2}O + MnCl_{2} + Cl_{2}](https://tex.z-dn.net/?f=MnO_%7B2%7D%20%2B%20HCl%20%5Crightarrow%20H_%7B2%7DO%20%2B%20MnCl_%7B2%7D%20%2B%20Cl_%7B2%7D)
Here, number of atoms on reactant side are as follows.
Number of atoms on product side are as follows.
To balance this equation, multiply HCl by 4 on reactant side and multiply
by 2 on product side. Therefore, the equation can be rewritten as follows.
![MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}](https://tex.z-dn.net/?f=MnO_%7B2%7D%20%2B%204HCl%20%5Crightarrow%202H_%7B2%7DO%20%2B%20MnCl_%7B2%7D%20%2B%20Cl_%7B2%7D)
Hence, number of atoms on reactant side are as follows.
Number of atoms on product side are as follows.
Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.
Thus, we can conclude that when maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is
.
Answer:
Generally, observed behavior that can be formulated into a statement, sometimes mathematical in nature, is called a natural law- D.