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Monica [59]
2 years ago
14

Mars have more gravity than earth? True or false?

Chemistry
2 answers:
tiny-mole [99]2 years ago
7 0

Answer:

false

Explanation:

earth is larger than mars so it has more gravity

irinina [24]2 years ago
5 0

Answer: false

Explanation:

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What are chemical formulaes?<br> give your own response!!
lbvjy [14]

Answer:

is a way of presenting information about the chemical proportions of atoms

Explanation:

8 0
2 years ago
Joanna is performing a reaction that generates a moderate amount of hydroxide. To mimic biological conditions (most bodily fluid
Nady [450]

Answer:

As for your question, I know to forget to put the options, specifically that your question is incomplete.

Explanation:

Although it could help you by telling you that always a reaction that seeks to balance the pH, and achieve neutrality ... It is necessary to achieve a concentration of OH equal to that of H +, in this way the hydroxyl and the protons.

7 0
3 years ago
What does AuCl, Gold (I) Chloride, decompose into?
Alexxx [7]

Answer:

Gold

Explanation:

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6 0
3 years ago
Be sure to answer all parts.
Liula [17]

A. The patch's area in square kilometers (km²) is 1.61×10⁻⁹ km²

B. The cost of the patch to the nearest cent is 734 cents

<h3>A. How to convert 16.1 cm² to square kilometers (km²)</h3>

We can convert 16.1 cm² to km² as illustrated below:

Conversion scale

1 cm² = 1×10⁻¹⁰ km²

Therefore,

16.1 cm² = 16.1 × 1×10⁻¹⁰

16.1 cm² = 1.61×10⁻⁹ km²

Thus, 16.1 cm² is equivalent to 1.61×10⁻⁹ km²

<h3>B. How to determine the cost in cent</h3>

We'll begin by converting 16.1 cm² to in². This can be obtained as illustrated below:

1 cm² = 0.155 in²

Therefore,

16.1 cm² = 16.1 × 0.155

16.1 cm² = 2.4955 in²

Finally, we shall the determine the cost in centas fo r llow:

  • Cost per in² = $2.94 = 294 cent
  • Cost of 2.4955 in² =?

1 in² = 294 cent

Therefore,

2.4955 in² = 2.4955 × 294

2.4955 in² = 734 cents

Thus, the cost of the patch is 734 cents

Learn more about conversion:

brainly.com/question/2139943

#SPJ1

6 0
1 year ago
Arrange the following molecules in order of increasing bond polarity (highest bond polarity at the bottom):
Tom [10]
NF3– 0.94– third
NCl3–0.12– second
NBr3–0.08– first
CF4–1.43– fourth

NBr3—NCl3—NF3—CF4
Lowest. Highest
4 0
2 years ago
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