Answer:
69.14% probability that the diameter of a selected bearing is greater than 84 millimeters
Step-by-step explanation:
According to the Question,
Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.
- In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ
we have μ=87 , σ=6 & X=84
- Find the probability that the diameter of a selected bearing is greater than 84 millimeters
This is 1 subtracted by the p-value of Z when X = 84.
So, Z = (84-87)/6
Z = -3/6
Z = -0.5 has a p-value of 0.30854.
⇒1 - 0.30854 = 0.69146
- 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.
Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)
Welcome
d the answer is 73 degrees
Answer:
D
Step-by-step explanation:
hi again
because the cornets show that -4 and -2 are also by -4 and -6 so that would =x+1 and x-5
hope this helps have a good day
love, The chris mac
Answer & Step-by-step explanation:
2a - b : 2a + b = 1 : 2
2a - b = 1
- Elimination
2a + b = 2
-b - (b) = -1
-2b = -1
b = 0.5
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2a + b = 2 Substitution
2a + 0.5 = 2
2a = 1.5
a = 0.75
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a:b
0.75 : 0.5
or
3/4 : 1/2
Hope this helps!!!
Answer:
D
Step-by-step explanation: always remember that sign as irrational
