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Rzqust [24]
3 years ago
15

Please help me with these geometry questions.

Mathematics
1 answer:
sashaice [31]3 years ago
7 0

Answer:

1)2(lb+bh+hl)

=2(17*12+12*8+8*17)

=2(204+96+136)

=2*436

=872 in^2

2)2*pi*r(r+h)

=2*3.14*14(14+29)

=6.28*14(43)

=6.28*14*43

=3780.56 mm^2

3)A=11*4.3+3*6 +3*8+11*3(Area of each plane figure -triangle and rectangle)

=47.3+18+24+33

=122.3cm^3

4)h*(sum of II sides)+14*8+19*8+14*8+25(Area of plane surface-trapezium,rectangle,square)

=12.1(19+5)+112+152+112+25

=12.1*24+401

=290.4+401

=691.4ft^2

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In trapiziod ABCD with bases AB and DC , diagonals intersect at point O. Find the length of diagonal BD, if BO=6 cm and A/O=3/1
ElenaW [278]

Answer:

the length of the diagonal BD is 8 cm

Step-by-step explanation:

The computation of the length of diagonal BD is as follows

Here the trapezoid diagonals divides each other in an equivalent ratio

So, equation would be

AO ÷ OC = OB ÷ OD

Now put there values to the above equation

3 ÷ 1 = 6 ÷ OD

3OD = 6

Now divided it by 3 in both the sides

OD = 2

Now the BD would be

= BO + OD

= 6 +  2

= 8 cm

hence, the length of the diagonal BD is 8 cm

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The perimeter of a rectangle is 32 meters. The length is 5 less than twice the width. Find the length and the width of the recta
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