The excess reactant is Aluminum.
<u>Explanation:</u>
We have to write the balanced equation as,
4 Al+ 3 O₂ → 2 Al₂O₃
According to the molar ratio 4: 3, from the given balanced equation, we can say that 4 atoms of Al reacted with 3 molecules of oxygen.
Given that 10 atoms of aluminum reacts with 6 molecules of oxygen, as per the ratio only 8 atoms of Aluminum is required to react with 6 molecules of oxygen, so excess reactant is Aluminum.
Answer:
Solids, liquids, gases - all matter - are made up of atoms (or other things, like molecules, that are made from atoms)! ELEMENTS are the kinds of atoms that we can have. Carbon is an element, hydrogen is an element, and so is oxygen. ... Atoms can join together - they form bonds together - to make MOLECULES.
Answer:
What atoms are present in carbon tetrachloride?
There is 1 carbon, and 4 chlorine atoms (or chloride ions if you want to get technical). Tetra means 4 in Greek.
hope that helps❤
Firstly, we need to convert 3g aspartame into moles aspartame. In order to do this we have to find the molecular mass of aspartame (the total weight of each atom of the molecule combined. This figure can be used to construct a conversion factor so that the grams may be converted into moles. Molecular weights for each atom can be found on any periodic table. Avagadro's number (6.022*10^23) is a constant value that expresses the number of molecules in one mole of a substance.
The molecular weight for aspartame is 294.3 grams per mole.
The process of finding how many atoms of H there are in 3.00g of aspartame would be like this:
1. 3g * 1mol/294.3g = .01mol aspartame (this is converting grams to moles)
2. .01mol * 6.022*10^23 = 6.022*10^21 (This is finding the number of molecules)
3. (6.022*10^21) * 18 = 1.08*10^23
This 3rd calculation is done because in part 2, you calculated the number of molecules of aspartame there were in 3g. In each molecule of aspartame there are 18 hydrogen atoms. So the final answer is:
1.08*10^23 hydrogen atoms.
Answer: The specific heat capacity of chromium is 
Explanation:

As we know that,

.................(1)
where,
q = heat absorbed or released
= mass of chromium = 15.5 g
= mass of water = 55.5 g
= final temperature =
= temperature of chromium = 
= temperature of water = 
= specific heat of chromium= ?
= specific heat of water= 
Now put all the given values in equation (1), we get
![-15.5\times c_1\times (19.5-18.9)=[55.5\times 4.184\times (19.5-100)]](https://tex.z-dn.net/?f=-15.5%5Ctimes%20c_1%5Ctimes%20%2819.5-18.9%29%3D%5B55.5%5Ctimes%204.184%5Ctimes%20%2819.5-100%29%5D)

The specific heat capacity of chromium is 