The volume of the cone can be calculated as follows:
volume of cone = (1/3) x pi x (radius)^2 x height .......> equation 1
We know that the height is twice the diameter, therefore:
h = 2d .............> equation 2
we also know know that the radius is half the diameter:
r = (1/2) d
d = 2r ...................> equation 3
Substitute with equation 3 in equation 2, we get:
h = 2d = 2 (2r)
h = 4r
r = (1/4) h................> equation 4
Substitute with equation 4 in equation 1, we get:
volume of cone = (1/3) x pi x (radius)^2 x height
= (1/3) x pi x (0.25 h)^2 x h
= (1/3) x pi x (1/16) h^2 x h
= (1/48) x pi x h^3
Answer:
combustion or/and oxidation
Explanation:
Answer: The rock formed from cooling lava.
Explanation:Extrusive igneous rocks, also known as volcanic rocks, are formed at the crust's surface as a result of the partial melting of rocks within the mantle and crust.
The reaction for the formation of MgO(s):
2 Mg (s) + O2(g) -à
2MgO(s) ΔH = -601.24
kJ/mol
<span>The enthalpy
information is taken from: http://webbook.nist.gov/cgi/inchi?ID=C1309484&Mask=2</span>
From the equation and with an enthalpy change of -231 kJ:
-231 kJ * 2 mol Mg * (1/-601.24 kJ/mol) = 0.76841 mol Mg
Then, with the molar mass of MgO = 40.3,
0.76841 mol Mg *(2 mol MgO/2 mol Mg)* 40.3 g/mol MgO = <span>30.967 g MgO</span>
One reason could be that the water in this experiment, didn’t boil, but instead became a “chemical reaction” from atmospheric pressure which is normal.
While heating two different samples, of
sea level water it decides on a temperature of 102°C and the other boils at 99.2°C. Basically calculating of the percent error.