jane starts to blink her eyes when her brother shines a flashlight at her. why does jane start blinking her eyes

Ben works as a medical assistant. He needs to take a patient's vitals, but the patient is refusing to cooperate. He hasn't exper

mariarad [96]

Answer:

THE CORRECT ANSWER IS COMMAND.HOPE IT HELP YOU

3 0

2 years ago

Calculate the volume of liquid in the tank sketched below. Give your answer in liters, and round to the nearest 0.1 L.

wariber [46]

Answer:

1.3 L

Explanation:

The volume of a rectangular cube can be calculated using the following formula:

Volume (L) = length (cm) x width (cm) x height (cm)

Keep in mind that 1 L = 1,000 cm³.

Before you can plug the values into the equation, you need to make sure they all have the same unit. Since the length is in meters (m), you need to first convert it to centimeters.

1 meter = 100 cm

0.159 m 100 cm
--------------- x ---------------- = 15.9 cm
1 m

Now, you can solve for the volume. To find the answer is the unit liters, you need to divide the volume by 1,000.

Volume = l x w x h

Volume = 15.9 cm x 10.5 cm x 7.7 cm

Volume = 1,285.5 cm³

Volume = 1.2855 L ------> Volume = 1.3 L

7 0

2 years ago

What is the mass of 2.40 moles of magnesium chloride, mgcl2

LiRa [457]

Hey there!

MgCl₂

Find molar mass of magnesium chloride.

Mg: 1 x 24.305

Cl: 2 x 35.453

--------------------

95.211 grams

One mole of magnesium chloride has a mass of 95.211 grams.

We have 2.40 moles.

2.40 x 95.211 = 228.5

To 3 sig figs this is 229.

The mass of 2.40 moles of magnesium chloride is 229 grams.

Hope this helps!

4 0

3 years ago

sample of atmospheric gas collected at an industrial site is stored in a 250 mL amber glass bottle that has a pressure of 1.02 a

Nady [450]

Answer:- New pressure is 0.942 atm.

Solution:- The volume of the glass bottle would remain constant here and the pressure will change with the temperature.

Pressure is directly proportional to the kelvin temperature. The equation used here is:

$P_1T_2=P_2T_1$

Where, $T_1$ and $T_2$ are initial and final temperatures, $P_1$ and $P_2$ are initial and final pressures.

$T_1$ = 20.3 + 273.15 = 293.45 K

$T_2$ = -2.0 + 273.15 = 271.15 K

$P_1$ = 1.02 atm

$T_2$ = ?

Let's plug in the values in the equation and solve it for final pressure.

$1.02atm(271.15K)=P_2(293.45K)$

$P_2=\frac{1.02atm*271.15K}{293.45K}$

$P_2$ = 0.942 atm

So, the new pressure of the jar is 0.942 atm.

5 0

3 years ago

Which of the following statements is true? A) This reaction will be spontaneous only at high temperatures. B) This reaction will

viktelen [127]

Answer:

D) This reaction will be nonspontaneous only at high temperatures.

Explanation:

According the equation of Gibb's free energy -

∆G = ∆H -T∆S

∆G = is the change in gibb's free energy

∆H = is the change in enthalpy

T = temperature

∆S = is the change in entropy .

And , the sign of the ΔG , determines whether the reaction is Spontaneous or non Spontaneous or at equilibrium ,

i.e. ,

if

ΔG < 0 , the reaction is Spontaneous

ΔG > 0 , the reaction is non Spontaneous

ΔG = 0 , the reaction is at equilibrium

The reaction has the value for ∆H = negative , and ∆S = negative ,

Now ,

∆G = ∆H -T∆S

= ( - ∆H ) - T( - ∆S )

= ( - ∆H ) +T( ∆S )

Now, for making the reaction Spontaneous ΔG = negative ,

Hence ,

The temperature is low, then the value for ΔG will be negative , i.e. , Spontaneous reaction .

And , vice versa , at higher temperature , the reaction will have ΔG positive , and the reaction will be non -Spontaneous reaction .

The standard free energy of formation will be zero , only for the compounds that are in their pure form ,

Hence , Al(s) will have ΔG = 0 .

7 0

3 years ago