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3 years ago

The concentration of the solid phase _____ the quantity present.

2 answers:

5 0

The concentration of the solid phase always remains the same regardless of the quantity present. Most of the chemical reactions and separation systems involve the transport of more or one components in solid phase.
For example, in the process of solid catalyzed reactions, the result of solid phase transport might be negligible though it is hard to identify it in the rate of data in the analysis.

Stels [109]3 years ago

4 0

Answer: Option (b) is the correct answer.

Explanation:

A solution that contains more number of solute particles than the solvent particles is known as a concentrated solution.

For example, concentrated solution of sulfuric acid.

On the other hand, a solution that contains less number of solute particles than the solvent particles is known as a dilute solution.

For example, a dilute solution of HCl.

Hence, we can conclude that concentration of a substance changes with change in the amount of solute.

Therefore, the concentration of the solid phase changes with the amount of the quantity present.

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Answer: high iridium levels in a 66- million-year-old clay layer in Denmark and Italy

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3 years ago

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Answer all 5 questions, please

klemol [59]

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3 years ago

The thallium (present as Tl2SO4) in a 9.486-g pesticide sample was precipitated as thallium(I) iodide. Calculate the mass percen

tino4ka555 [31]

Answer: The mass percentage of $Tl_2SO_4$ is 5.86%

Explanation:

To calculate the mass percentage of $Tl_2SO_4$ in the sample it is necessary to know the mass of the solute ( $Tl_2SO_4$ in this case), and the mass of the solution (pesticide sample, whose mass is explicit in the letter of the problem).

To calculate the mass of the solute, we must take the mass of the $TlI$ precipitate. We can establish a relation between the mass of $TlI$ and $Tl_2SO_4$ using the stoichiometry of the compounds:

$moles\ of\ TlI = \frac{0.1824 g}{331.27\frac{g}{mol} } = 5.51*10^{-4}\ mol.$

Since for every mole of Tl in $TlI$ there are two moles of Tl in $Tl_2SO_4$ , we have:

$moles\ of\ Tl_2SO_4 = 2 * moles\ of\ TlI = 1,102*10^{-3}\ mol$

Using the molar mass of $Tl_2SO_4$ we have:

$mass\ of\ Tl_2SO_4 = 1,102*10^{-3}\ mol * 504.83\ \frac{g}{mol}= 0.56\ g$

Finally, we can use the mass percentage formula:

$mass\ percentage = (\frac{solute\ mass}{solution\ mass} )*100 = (\frac{mass\ of\ Tl_2SO_4}{pesticide\ sample\ mass})*100 = (\frac{0.56g}{9.486g})*100 = 5.86\%$

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3 years ago

Chemistry question! Please help!

Illusion [34]

When a solid (solute) comes in contact with the liquid (solvent), the solute goes about C) dissolution, in which the solid dissolves into the liquid.

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3 years ago

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This is the chemical formula for methyl acetate: CH32CO2. Calculate the mass percent of hydrogen in methyl acetate. Round your a

WITCHER [35]

<u>Answer:</u> The mass percent of hydrogen in methyl acetate is 8 %

<u>Explanation:</u>

The given chemical formula of methyl acetate is $CH_3COOCH_3$