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Alex_Xolod [135]
3 years ago
12

In the Bronsted-Lowry model of acids and bases, an _____ is a hydrogen donor and a _____ is a hydrogen acceptor.

Chemistry
1 answer:
Natasha_Volkova [10]3 years ago
4 0

Answer:

According to Bronsted-lowry concept  an acid is a hydrogen donnor and a base is a hydrogen acceptor.

Explanation:

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PH & POH
Mashcka [7]

Answer:

<h2>4.0 </h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ { H}^{+}]

From the question we have

ph =  -  log(9.25 \times  {10}^{ - 5} )  \\  = 4.03385

We have the final answer as

<h3>4.0</h3>

Hope this helps you

5 0
3 years ago
Sodium-25 was to be used in an experiment, but it took 3.0 minutes to get the sodium from the reactor to the laboratory. If 8.0
Ksenya-84 [330]

Sodium-25 after 3 minutes : 1.0625 mg

<h3>Further explanation</h3>

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

T = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

<h3 />

No=8 mg

t1/2=60 s

T=3 min=180 s

\tt Nt=No\dfrac{1}{2}^{T/t1/2}\\\\Nt=8.5\dfrac{1}{2}^{180/60}\\\\Nt=8.5(\dfrac{1}{2})^3\\\\Nt=1.0625~mg

5 0
2 years ago
The caloric content of 0.50 cup of cottage cheese is 1.10 x 102 kcal. This is the amount of energy released when 0.50 cup of cot
V125BC [204]

Answer:

A piece of unknown solid substance weighs 437.2 g, and requires 8460 J to increase its temperature from 19.3 °C to 68.9 °C.

What is the specific heat of the substance?

If it is one of the substances found in Table 8.1.1, what is its likely identity?

3 0
3 years ago
Question 3 (1 point)
irina1246 [14]

false

Explanation:

i took the test

4 0
2 years ago
Read 2 more answers
Consider the following system at equilibrium where H° = 111 kJ/mol, and Kc = 6.30, at 723 K.
Rashid [163]

Answer:

1) The value of Kc:

C. remains the same.

2) The value of Qc:

A. is greater than Kc.

3) The reaction must:

B. run in the reverse direction to restablish equilibrium.

4) The concentration of N2 will:

B. decrease.

Explanation:

Hello,

In this case, by means of the Le Chatelier's principle which is based on the shift a chemical reaction could have under some modifications, we have:

1) The value of Kc:

C. remains the same, since it just depend the reaction's thermodynamics as it is computed via:

ln(K)=\frac{\Delta _RG}{RT}

2) The value of Qc:

A. is greater than Kc, since the reaction quotient is:

Qc=\frac{[N_2][H_2]^3}{[NH_3]^2}

Thus, the lower the concentration of ammonia, the higher Qc, making Qc>Kc.

3) The reaction must:

B. run in the reverse direction to restablish equilibrium, since ammonia was withdrawn and should be regenerated to reach the equilibrium.

4) The concentration of N2 will:

B. decrease, since less reactant is forming the products.

Best regards.

8 0
3 years ago
Read 2 more answers
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