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3 years ago

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A 1200 kg truck is moving to the right at the speed of 30 m/s. It hit another identical truck that was at rest. The two trucks s

tick together and move to the right at a speed of 15 m/s.

1 answer:

Marrrta [24]3 years ago

4 0

Answer:

ok wht is the question

Explanation:

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Atoms seldom exist as independent particles in nature because...

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<h3><u>Answer;</u></h3>

C) atoms are more stable when they combine with other atoms

<h3><u>Explanation</u>;</h3>

Atoms are the smallest particles of an element that can take part in a chemical reaction.
<em><u>Atoms seldom exist as independent particles in nature. Nearly all substances are made up of combinations of atoms that are held together by chemical bonds, which are forces of attractions between the nuclei and valence electrons of different atoms that join the atoms together.</u></em>

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3 years ago

1) When making a digital animation of a person running on a sidewalk in a scene, which parameter would be an initial condition?

lbvjy [14]

Answer:

The position of the person's feet. a running shoe company studying how different surfaces affect the life of a shoe tread

Explanation:

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3 years ago

konstantin123 [22]

Answer:

i need help too

Explanation:

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3 years ago

The 360-turn primary coil of a step-down transformer is connected to an ac line that is 120 V (rms). The secondary coil is to su

ZanzabumX [31]

Answer:

N₂ = 19 turns

Explanation:

A transform is a system with two different windings where the variation of the magnetic beam is the same, if there are no losses in the system we can use Faraday's law

V₁ = -N₁ $\frac{d \Phi_B }{dt}$

v₂ = - N₂ \frac{d \Phi_B }{dt}

$\frac{V_1}{N_1} = \frac{V_2}{N_2}$

in this case we look for the number of turns in the second winding

N₂2 = $N_1 \ \frac{ V_2}{V_1}$

calculate us

N₂ = 360 6.30/ 120

N₂ = 18.9 turn

The number of turns must be an integer

N₂ = 19 turns

8 0

3 years ago

Cart A, with a mass of 0.20 kg, travels on a horizontal air trackat 3.0m/s and hits cart B, which has a mass of 0.40 kg and is i

inysia [295]

Answer:

$\large \boxed{\text{C. 2.3 m/s}}$

Explanation:

Data:

$m_{\text{A} } = \text{0.20 kg};\,v_{\text{Ai}} = \text{3.0 m/s}\\m_{\text{B} } = \text{0.40 kg};\,v_{\text{Bi}} = \text{2.0 m/s}\\$

Calculation:

This is a perfectly inelastic collision. The two carts stick together after the collision and move with a common final velocity.

The conservation of momentum equation is

$\begin{array}{rcl}m_{\text{A}}v_{\text{Ai}} +m_{\text{B}} v_{\text{Bi}}&=&(m_{\text{A}} + m_{\text{B}})v_{\text{f}}\\0.20\times 3.0 + 0.40\times 2.0 & = & (0.20 + 0.40)v_{\text{f}}\\0.60 + 0.80 & = & 0.60v_{\text{f}}\\1.40 & = & 0.60v_{\text{f}}\\v_{\text{f}}&=& \dfrac{1.40}{0.60}\\\\& = & \textbf{2.3 m/s}\\\end{array}\\\text{The centre of mass has a velocity of $\large \boxed{\textbf{2.3 m/s}}$}$

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3 years ago