Answer:
Mass of water,
Explanation:
Given that,
Surface area of the reservoir, A = 30 km² = 3 × 10⁷ m²
Average depth, d = 49 m
The volume of the reservoir is V such that,
We have to find the mass of water is held behind the dam. It can be calculated using the expression for density. We know that density of water, d = 1000 kg/m³
Density,
Hence, this is the required solution.
I believe that is a Geiger Counter
Answer: The magnetic field is 4×10^-4T
Explanation:
Using the magnetic field equation
B=μI/2πr
B= magnetic field =?
l= current in the wire=2.0A
r= distance from the axis of wire=1.0mm= 0.001m
μ=magnetic permeability =4π×10^-7N/m
B= (4π×10^-7 × 2.0)/(2π × 0.001)
B= 4×10^-4T
Therefore the magnetic field is 4×10^-4T